Ubuntu – Print specific words/numbers via grep/cut commands

command linegreptext processing

I have a file test.txt, which contains the following result:

service_name1= apple/ball/cat/dog/egg/12.34.56/ball/apple
service_name2= fan/girl/house/ice/joker/23.45.67/fan/girl

and so on up to service_name1500

I want output like :

egg 12.34.56
joker 23.45.67

and so on: the version number along with the word before that.

Best Answer

This should be a simple cut job:

cut -d/ -f5,6 --output-delimiter=" "

-d/ sets the input delimiter as /
-f5,6 outputs only the 5th and 6th field
--output-delimiter=" " sets the output delimiter as a space

Same thing with awk, awk by default sets the output field separator as space:

awk -F/ '{print $5,$6}'

Example:

% cat file.txt
service_name1= apple/ball/cat/dog/egg/12.34.56/ball/apple
service_name2= fan/girl/house/ice/joker/23.45.67/fan/girl

% cut -d/ -f5,6 --output-delimiter=" " file.txt
egg 12.34.56
joker 23.45.67

% awk -F/ '{print $5,$6}' file.txt
egg 12.34.56 
joker 23.45.67

Related Solutions

Ubuntu – How to pass list of names to be searched by grep using xargs

You can use -I to tell xargs to use a particular character or sequence of characters as a placeholder for the argument. From man xargs:

   -I replace-str
          Replace occurrences of replace-str in the initial-arguments with
          names read from standard input.  Also, unquoted  blanks  do  not
          terminate  input  items;  instead  the  separator is the newline
          character.  Implies -x and -L 1.

A common choice is {} so

cat nameslist.txt | xargs -I {} grep {} targetfile.txt

or (without the useless use of cat)

< nameslist.txt xargs -I {} grep {} targetfile.txt

However, assuming your list has one name per line you don't need xargs here at all - grep can read a list of patterns (or fixed strings, with the -F option) from a file:

grep -F -f nameslist.txt targetfile.txt

Best Answer

Related Solutions

Ubuntu – How to pass list of names to be searched by grep using xargs

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