Ubuntu – List all human users

command lineusers

How can I list all human users that I've created? I've tried cat /etc/passwd and it just lists a lot of stuff.

Best Answer

Human users have UIDs starting at 1000, so you can use that fact to filter out the non-humans:

cut -d: -f1,3 /etc/passwd | egrep ':[0-9]{4}$' | cut -d: -f1

This cuts the first (username) and third (UID) colon-delimited fields from /etc/passwd, then filters for the resulting lines which end with a colon and four digits, then cuts the first (username) field from that, leaving you with a list of users with UIDs between 1000 and 9999.

If you have more than nine thousand users on your system, this will fail - but it's necessary to restrict the result to 4-digit UIDs in order not to catch nobody (UID 65534).

Related Solutions

Ubuntu – Shell script for list of users by groups

Use this script:

#! /bin/bash
#
for i in $(cat /etc/passwd  | cut -d: -f1); do
   echo -n $i ": "
   grep $i /etc/group | cut -d: -f1 | tr "\n" " "
   echo
done

It will list all users in the system (included system) and print the list of groups near them. With a trivial modification you can print the numeric id too.

Ubuntu – Command to list all users with their UID

List all users with a /home folder:

awk -F: '/\/home/ {printf "%s:%s\n",$1,$3}' /etc/passwd

or all users with a UID >= 1000:

awk -F: '($3 >= 1000) {printf "%s:%s\n",$1,$3}' /etc/passwd

a combination

awk -F: '/\/home/ && ($3 >= 1000) {printf "%s:%s\n",$1,$3}' /etc/passwd

or for all entries

awk -F: '{printf "%s:%s\n",$1,$3}' /etc/passwd

More information here

Best Answer

Related Solutions

Ubuntu – Shell script for list of users by groups

Ubuntu – Command to list all users with their UID

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