I want to make a list of my subdirectories. When I execute the following for loop, the first directory name occurs two times
for d in */; do
echo $d >> directories.txt
done
The output is like :
ONE/
TWO/
ONE/
Where is the problem?
Ubuntu – How to write out all directory names into a text file
bash
Related Solutions
To check only for t1.csv, you can use:
find . -name 't1.csv'
Now, to go in the first directory where t1.csv file is found, you can use:
cd $(dirname $(find . -name 't1.csv' 2>/dev/null | head -1) 2>/dev/null)
Your description seems odd: If you get just proj1, how do you know what its parent directory is?
Anyway, to give you what you asked for:
# for me, this takes a looooooong time [1]. Do it once and cache it
mapfile -t _all_dir_names < <( find ~ -type d -printf "%f\n" )
# the function you want completion for
myfunc () { echo hello world $*; }
# the completion function
complete_myfunc() {
local dir cur=${COMP_WORDS[COMP_CWORD]}
COMPREPLY=()
for dir in "${_all_dir_names[@]}"; do
if [[ $dir == "$cur"* ]]; then
printf -v dir "%q" "$dir" # protect whitespace in the dir name
COMPREPLY+=("$dir")
fi
done
}
# registering the completion
complete -F complete_myfunc myfunc
[1]: 2 minutes, 66782 directories
Best Answer
Improving you current code, this command should be helpful:
To remove the
./from the output: