Ubuntu – How to create a select menu in a shell script

bashcommand linescripts

I'm creating a simple bash script and I want to create a select menu in it, like this:

$./script

echo "Choose your option:"

1) Option 1  
2) Option 2  
3) Option 3  
4) Quit

And according to user's choice, I want different actions to be executed. I'm a bash shell scripting noob, I've searched the web for some answers, but got nothing really concrete.

Best Answer

#!/bin/bash
# Bash Menu Script Example

PS3='Please enter your choice: '
options=("Option 1" "Option 2" "Option 3" "Quit")
select opt in "${options[@]}"
do
    case $opt in
        "Option 1")
            echo "you chose choice 1"
            ;;
        "Option 2")
            echo "you chose choice 2"
            ;;
        "Option 3")
            echo "you chose choice $REPLY which is $opt"
            ;;
        "Quit")
            break
            ;;
        *) echo "invalid option $REPLY";;
    esac
done

Add break statements wherever you need the select loop to exit. If a break is not performed, the select statement loops and the menu is re-displayed.

In the third option, I included variables that are set by the select statement to demonstrate that you have access to those values. If you choose it, it will output:

you chose choice 3 which is Option 3

You can see that $REPLY contains the string you entered at the prompt. It is used as an index into the array ${options[@]} as if the array were 1 based. The variable $opt contains the string from that index in the array.

Note that the choices could be a simple list directly in the select statement like this:

select opt in foo bar baz 'multi word choice'

but you can't put such a list in a scalar variable because of the spaces in one of the choices.

You can also use file globbing if you are choosing among files:

select file in *.tar.gz
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