Ubuntu – Batch rename with id shifting

batch-renamecommand line

I need to batch rename bunch of files with id in name, adding a constant number to id

 <id>-xxx.txt => <id+shift>-yyy.txt

Any ideas how to make it? Some awk maybe?

Best Answer

constant=42
for f in *.txt; do    # choose your pattern as appropriate.
    IFS='-.' read id suffix ext <<< "$f"
    newname="$(( 10#$id + constant ))-yyy.$ext"
    echo mv "$f" "$newname"
done

I added "10#" in the arithmetic expression to ensure the number is treated as base-10 even if it begins with a zero.

If this doesn't meet your needs, please provide more requirements in the question.

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Ubuntu – Using text list to batch-rename files

This looks like a job for xargs.

If your file is formatted like this:

old_file1 new_file1
old_file2 new_file2

then you can do xargs -a your_file -n 2 mv.

Ubuntu – How to batch rename files (images) based on CSV file

This should work for you:

sed 's/"//g' files.csv | while IFS=, read orig new; do mv "$orig" "$new"; done

Explanation:

sed 's/"//g' files.csv : remove the quotes
IFS=, : split the input on ,
while read orig new; do ... done : This will read each input line, split it on the value of $IFS (here a comma) and save the 1st field as $orig and the rest as $new.
mv "$orig" "$new" : this will rename the files as requested.

If your file only contains file names (like orig.jpg) and no paths (not /home/take2/orig.jpg or similar), the command above will only affect files in your current directory. So, you need to open a terminal, cd to the target directory and run it there.

Test first:

To test this, you can do a dry run first by printing the commands that will be run without actually executing them:

sed 's/"//g' files.csv | while IFS=, read orig new; do echo mv "$orig" "$new"; done

Best Answer

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Ubuntu – Using text list to batch-rename files

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