What or is there a command to open the action center settings?
I want a command that opens this screen specifically. I know that I can open the generic action center by running "wscui.cpl", but that is not specifically what I want to do.
Any ideas?
Windows – Command line argument to open Action Center Settings
action-centercommand linewindows
Related Solutions
You can hide the Action Center icon with the following command:
reg add HKLM\Software\Microsoft\Windows\CurrentVersion\Policies\Explorer /v HideSCAHealth /t REG_DWORD /d 0x1
It won't disable messages (to do that you'd have to edit a binary registry value), but they won't be displayed anymore.
I'm asking about why the notification "toasts" (again, I don't know the Windows terminology) are never making it into the Action Center in the first place.
The toast notifications are transient by definition, so they vanish after a bit of time, unless they require action.
From MS:
"A toast notification is a transient message to the user that contains relevant, time-sensitive information and provides quick access to related content in an app."
It's up to the app's developers to pick the notification type. Since the Action Center is an extension of the toast notification system that existed in Windows previously (since like XP), notifications triggered using old APIs/methods will act like they used to, which includes not being added to the Action Center list.
You can control how long transient toast notifications stay visible via Settings -> Ease of Access -> Other options -> Show notifications for, where you can set them to last onscreen for up to 5 minutes.
Best Answer
There is no direct command to do that but you can use a script like this one.
Create a new text file, paste this code in it:
Save it under this name
wscuisettings.vbs. double click on the file.