Show only odd lines with cat

bash

HI,

probably is this something very easy, but I do not get the point now. In Linux, shell, given a text file, how can I do something like, cat filename so I only see the first line, the third line, 5, 7, 9 and so on?

if not with cat, with another command

Thanks

Best Answer

Using awk: awk 'NR % 2 == 0' filename

Edit: removed {print}, as shown in ghostdog74's answer and commented on by Roberto Bonvallet.

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In AWK, you could do something like this:

awk '($1 == last) || (last == "") {sum += $2}
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                                  {last = $1}
     END                          {print last " " sum}' huge_text_file.txt

How to cat/print a file except the last 2 lines

Use the head command from coreutils:

head -n -2

See info head for more.

Best Answer

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How to cat/print a file except the last 2 lines

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