Read multiple words in linux bash script

bashlinuxshell-script

I am prompting the user to enter two words separated by space.
I am using read name to read name and then read last to read last word
the user inputs like name last separated by space. But read seems to be reading the
whole line. How can I read the first words and the second word separately?

Best Answer

In general, you can read into an array.

$ read -ra arr
sadf / asdf \ wer
tomasz@fuji:~$ printf "%s\n" "${arr[@]}"
sadf
/
asdf
\
wer

Each line in this printf output corresponds to a single array item.

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Linux – How to make a Bash Script take an input before the script is invoked

#!/bin/bash

case $# in
0) echo -n "Hello $USER, welcome to the guestbook! Choose an option (sign|view|save|erase):     "
   read option ;;

1) option=$1 ;;

*) echo "Sorry, I didn't understand that (too many command line arguments)"
   exit 2 ;;

esac

if [ "$option" == "sign" ]; then
  python /usr/local/bin/guestbook.data/sign_guestbook.py

elif [ "$option" == "view" ]; then
  python /usr/local/bin/guestbook.data/view_guestbook.py

elif [ "$option" == "save" ]; then
  python /usr/local/bin/guestbook.data/save_guestbook.py

elif [ "$option" == "erase" ]; then
  python /usr/local/bin/guestbook.data/erase_guestbook.py

else
  echo "Sorry, I didn't understand that." 

fi

Best Answer

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