Linux – Sed replace string with variable

bashlinuxsed

Im trying to replace string with variable with this command but not works

sed '/AXG/s/;/${HOMEx}/g'

Please help me with this

Best Answer

Get rid of the single quotes. They prevent variable expansion.

sed "/AXG/s/;/${HOMEx}/g"

If HOMEx="test" this becomes: sed "/AXG/s/;/test/g"

Compare https://www.gnu.org/software/bash/manual/html_node/Double-Quotes.htm and https://www.gnu.org/software/bash/manual/html_node/Single-Quotes.html

Beware though: if the variable HOMEx contains something sed recognises you'll get an error. In this case the main things would be a backreference like "\1" or forward slash "/".

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Use sed to replace part of a string

You seem to be confusing shell patterns with regular expressions. In a shell pattern, * means zero or more of any character. In a regular expression, which is what sed expects in its patterns, * means zero or more of the previous atom. In your example, that atom is the =. So, sed is searching for user followed by zero or more = and replacing the matching string with user=bob. The pattern you want is user=.*, which is user= followed by any character (.) zero or more times, making your sed command:

sed -i 's/user=.*/user=bob/' myfile

Best Answer

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