Linux: list contents of sub directories with given name

greplinuxlsUbuntu

I'm using linux to analyze a windows directory structure. The structure is:

/Documents and settings
  /username1
    /My Documents
    ...
  /username2
    /My Documents
    ...
  ...

What command can I execute so that the contents (and sub folders) of all the "My Documents" directories are listed like:

/Documents and Settings/username1/My Documents/filename
/Documents and Settings/username1/My Documents/subdir/filename
/Documents and Settings/username2/My Documents/filename

Basically there are a ton of users but almost none have anything in their My Documents folder. I just want to find and show the contents of those user's that do have documents.

EDIT: Each "username" directory contains many sub directories. I only want to list the tree below the My Documents folder but do so for all usernames at once.

Best Answer

Combining the first two answers, use find and ls -R:

find "/Documents and settings" -name "My Documents" -exec ls -R {} \;

This will find all of the My Documents directories and list everything underneath them, with full pathnames. You need the quotes since the directory names have spaces in them.

Edit: An explination of how this works. It starts at /Documents and settings, looking for any file or directory that matches My Documents. For each one it finds, it substitutes the path for {} in the ls. The \; signifies the end of the command.

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