Linux – How to wrap this output in quotes

bashlinuxshell

I have the following command, which gives me 99% of what I want:

root@CA2UA5232QPZ:/# tail -3 newtag | awk '{print $1}'
v1.0.20170512.1
v1.0.20170712.1
v1.0.20170712.2
root@CA2UA5232QPZ:/#

But I need to tweak it so the output looks like this:

'v1.0.20170512.1'
'v1.0.20170712.1'
'v1.0.20170712.2'

Best Answer

You could pipe your output to sed:

tail -3 newtag| awk '{print $1}'| sed "s/^/'/;s/$/'/"

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If you want to use a pipe, then your python script would have to read from stdin. Your script doesn't do that. Instead it expects a file name on the command line. This can be accomplished using a shell feature called process substitution to connect the two together:

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<(...) denotes process substitution. What happens here is that the shell creates a file-like object that contains the output of the awk command. This file-like object even has a name. If you run the script, the output will see its name, passed to python as sys.argv[1], is something like:

/dev/fd/63

Tail/head all line except X last/first Lines

tail -n+3 outputs the last lines starting from the third one.

Best Answer

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Bash – How to pipe AWK command output to Python as first argument

Tail/head all line except X last/first Lines

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