When running defrag -a -v C:
on Windows 2008 R2, I got the following output:
Windows Disk Defragmenter Copyright (c) 2006 Microsoft Corp. Analysis report for volume C: Volume size = 40.00 GB Cluster size = 4 KB Used space = 13.94 GB Free space = 26.06 GB Percent free space = 65 % File fragmentation Percent file fragmentation = 19 % Total movable files = 73,181 Average file size = 233 KB Total fragmented files = 1,574 Total excess fragments = 5,611 Average fragments per file = 1.09 Total unmovable files = 21
The Percent file fragmentation value seems very strange to me. From the file counts, 1574 fragmented files is only 2% of the total number of files.
How does Windows calculate the Percent file fragmentation value?
Best Answer
It seems that:
Percent file fragmentation = Percent free space (after defragmentation) - Percent free space (before defragmentation)
In other words, the percent free space added by performing full defragmentation.
As you can see, 7 % = 31 % - 24 %:
On the other hand, when, after defragmenting a drive, the Percent free space does not change, nor the Percent file fragmentation does not change, even if the Total fragmented files number does change: