When I enter "firefox" in the windows run dialog (i.e. the dialog that appears when you hit windows+R), firefox will launch.
However, "firefox.exe" is not in my %path%
because when I type "firefox" in cmd.exe
, I get
'firefox' is not recognized as an
internal or external command, operable
program or batch file.
So apparently an executable doesn't need to be found in the windows %path%
in order to be discoverable by the run dialog. How does this work?
Best Answer
Apparently the run dialog checks not only the %path% environment variable, but also the "App Path" registry key. From a techrepublic article about the run dialog:
The relevant locations in the registry are
HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Windows\CurrentVersion\App Paths
andHKEY_CURRENT_USER\Software\Microsoft\Windows\CurrentVersion\App Paths
(this last one being specific to the user). You can add your own "app paths" there with regedit.