Delete the first known character in a string with sed

sed

How does one delete the first known character in a string with sed?

For example, say I want to delete the first character (which is @) in the string "@ABCDEFG1234"

I want sed to verify whether "@" exists as the first character. If so, it should delete the character.

Best Answer

sed 's/^@\(.*\)/\1/'

^ means beginning of the string

@ your known char

(.*) the rest, captured

then captured block will be substituted to output Sorry, can't test it at the moment, but should be something like that

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Sed + How to delete single character after other character in line by sed

 % echo "ABCDE 123 |@ TEST" | sed 's,|@,|,'

its essentially the same as your other question.

Delete all occurences of any word matching a partial string in sed

What about this one?

sed 's/\S*\(tom\|TOM\)\S*//g'

resp. in non-GNU versions of sed this should work:

sed 's/[a-zA-Z0-9_!]*[Tt][Oo][Mm][a-zA-Z0-9_!]*//g'

This will substitute all words (i.e. strings beginning with 0 or more non-whitespace characters (\S) followed by tom or TOM and again 0 or more non-whitespace characters) with an empty string.
Probably you should also remove double spaces:

sed 's/\S*\(tom\|TOM\)\S*//g;s/\(\s\)\s*/\1/g'

Best Answer

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Sed + How to delete single character after other character in line by sed

Delete all occurences of any word matching a partial string in sed

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