i'm trying to find out if there is a row which contains a specific date inside a JSON array
Let's say my data looks like this:
Table applications:
id | application_id | data
# Rows
1 | 1 | [{"data" : ["some", "data#1"], "date": "2016-04-21"}, {"data" : ["other", "data#1"], "date" : "2016-04-22"}]
2 | 2 | [{"data" : ["some", "data#2"], "date": "2016-04-21"}, {"data" : ["other", "data#2"], "date" : "2016-04-26"}]
3 | 1 | [{"data" : ["some", "data#3"], "date": "2016-04-22"}, {"data" : ["other", "data#3"], "date" : "2016-04-26"}]
4 | 3 | [{"data" : ["some", "data#4"], "date": "2016-04-26"}]
How can I find all the applications whose data contains the date '2016-04-26'
?
So basically I can do this:
select id, json_extract(`data`, "$[*].date") from applications
Which returns:
1 | ["2016-04-21", "2016-04-22"]
2 | ["2016-04-21", "2016-04-26"]
3 | ["2016-04-22", "2016-04-26"]
4 | ["2016-04-26"]
But if try to use json_extract
in the WHERE
clause I can only use it if I explicitly tell the array's key in the json_extract
's path argument, like so:
select * from applications where json_extract(`data`, "$[0].date") = "2016-04-26"
which correctly returns the row with id 4.
But if I try to use a wildcard in the path then it no longer works:
select * from applications where json_extract(`data`, "$[*].date") = "2016-04-26"
this should return the rows 2, 3, 4.
I tried many other options/variations but I can't seem to find a way to structure the query correctly.
Is something like this even possible with the current implementation of MySQL JSON?
Best Answer
One solution as provided by Morgan Tucker - @morgo is to use
json_contains
like so:For now the answer is OK, but i believe it can have some performance issues and feels a bit hackish to me (see the next query) - but I will deal with those when i get there :)
If I would need to query on a date range (from
2016-04-24
to2016-04-26
) I would need to add an invididualjson_contains
for each day in the time span like so:And this would return invalid data if I would have an
date
key nested somewhere elseSo if you have an different solution, I would like to know