The easiest way is to have a calendar
table, defined in the following way:
CREATE TABLE calendar
(
a_day date PRIMARY KEY
) ;
... and filled with all the relevant dates (i.e.: all days from 1990-1-1 to 2100-12-31). For the sake of simplicity, we will fill it only with year 2013:
INSERT INTO
calendar (a_day)
VALUES
('2013-01-01'),
('2013-01-02'),
('2013-01-03'),
('2013-01-04'),
('2013-01-05'),
-- everything up to
('2013-12-31') ;
At this point, you can just have a JOIN
with the two tables; with the join condition not being an equality, but a range condition:
SELECT
t.id, c.a_day
FROM
t
JOIN calendar c ON c.a_day BETWEEN t.start_date AND t.end_date
ORDER BY
t.id, c.a_day ;
... and get
id | a_day
-: | :---------
1 | 2013-01-14
1 | 2013-01-15
1 | 2013-01-16
1 | 2013-01-17
1 | 2013-01-18
2 | 2013-02-01
2 | 2013-02-02
2 | 2013-02-03
2 | 2013-02-04
You can see all the setup at dbfiddle here
You can use MAKEDATE()
, it makes the day_of_year
to a date.
Test:
mysql> SELECT * FROM cli_table;
+-------+--------------+-------------+-------+
| month | day_of_month | day_of_year | value |
+-------+--------------+-------------+-------+
| 1 | 1 | 1 | 23.00 |
| 1 | 2 | 2 | 22.95 |
| 12 | 31 | 365 | 23.12 |
+-------+--------------+-------------+-------+
3 rows in set (0.00 sec)
mysql> SELECT
-> MAKEDATE(YEAR(CURDATE()),day_of_year) AS Date,
-> value AS DayValue
-> FROM test.cli_table;
+------------+----------+
| Date | DayValue |
+------------+----------+
| 2015-01-01 | 23.00 |
| 2015-01-02 | 22.95 |
| 2015-12-31 | 23.12 |
+------------+----------+
3 rows in set (0.00 sec)
mysql>
You can try it in this Fiddle.
EDIT:
According of what you want, you can make it with pure SQL:
mysql> SELECT * FROM test.cli_table;
+-------+--------------+-------------+-------+
| month | day_of_month | day_of_year | value |
+-------+--------------+-------------+-------+
| 1 | 1 | 1 | 5.00 |
| 1 | 2 | 2 | 6.00 |
| 1 | 3 | 3 | 7.00 |
| 12 | 25 | 359 | 23.00 |
| 12 | 26 | 360 | 22.95 |
| 12 | 27 | 361 | 1.00 |
| 12 | 28 | 362 | 2.00 |
| 12 | 29 | 363 | 3.00 |
| 12 | 30 | 364 | 4.00 |
| 12 | 31 | 365 | 23.12 |
+-------+--------------+-------------+-------+
10 rows in set (0.00 sec)
mysql> SELECT
-> v.selected_date,
-> v.dayyear,
-> c.value AS DayValue,
-> c.day_of_year
-> FROM test.cli_table AS c
-> JOIN (SELECT
-> adddate('1970-01-01',t4.i*10000 + t3.i*1000 + t2.i*100 + t1.i*10 + t0.i) AS selected_date,
-> DAYOFYEAR(adddate('1970-01-01',t4.i*10000 + t3.i*1000 + t2.i*100 + t1.i*10 + t0.i)) AS dayyear
-> FROM
-> (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
-> (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
-> (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
-> (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3,
-> (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t4) AS v
-> ON (v.selected_date between '2015-12-25' AND '2016-01-03'
-> AND v.dayyear=c.day_of_year);
+---------------+---------+----------+-------------+
| selected_date | dayyear | DayValue | day_of_year |
+---------------+---------+----------+-------------+
| 2015-12-25 | 359 | 23.00 | 359 |
| 2015-12-26 | 360 | 22.95 | 360 |
| 2015-12-27 | 361 | 1.00 | 361 |
| 2015-12-28 | 362 | 2.00 | 362 |
| 2015-12-29 | 363 | 3.00 | 363 |
| 2015-12-30 | 364 | 4.00 | 364 |
| 2015-12-31 | 365 | 23.12 | 365 |
| 2016-01-01 | 1 | 5.00 | 1 |
| 2016-01-02 | 2 | 6.00 | 2 |
| 2016-01-03 | 3 | 7.00 | 3 |
+---------------+---------+----------+-------------+
10 rows in set (0.00 sec)
mysql>
Query Meaning:
SELECT
v.selected_date,
v.dayyear,
c.value AS DayValue,
c.day_of_year
FROM test.cli_table AS c
--- > This JOIN is generating all the dates between the selected_dates ('2015-12-25' AND '2016-01-03')
JOIN (SELECT
adddate('1970-01-01',t4.i*10000 + t3.i*1000 + t2.i*100 + t1.i*10 + t0.i) AS selected_date,
DAYOFYEAR(adddate('1970-01-01',t4.i*10000 + t3.i*1000 + t2.i*100 + t1.i*10 + t0.i)) AS dayyear
FROM
(select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
(select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
(select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
(select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3,
(select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t4) AS v
--- > Here I'm matching every dayyear of the generated dates with the cli_table.day_of_year.
ON (v.selected_date between '2015-12-25' AND '2016-01-03'
AND v.dayyear=c.day_of_year);
Best Answer
Typically the way you would do this is using another reference table to hold the product ID with a date reserved. Something like this:
Then you could join this table to the table you currently have to get the x most recent. Your SQL could look something like this: