I have 3 queries as follows:
For the date 2019-12-02, I am calculating 3 type of values. The total value for 2019-12-02 must be the sum of these 3 queries.
Q1
SELECT count(*)
FROM XAXBXC_charge_info_ABC_tbl
WHERE date = '2019-12-02'
AND cg_response_code = 0
Q2=>
SELECT count(*)
FROM XAXBXC_charge_info_ABC_tbl
WHERE date = '2019-12-02'
AND topup_id = 10
AND topup_cg_response_code LIKE '0'
Q3=->
SELECT count(*)
FROM XAXBXC_charge_info_ABC_tbl
WHERE date = '2019-12-02'
AND topup_id = 11
AND topup_cg_response_code LIKE '0'
I am trying to calculate and display sum as follows,
Date | Sum
2019-12-02| 234
eg:-
For a particular date, sum should be equal to the sum of Q1+Q2+Q3 and it must be grouped by the date column.
Can someone help me to achieve this? I have been stuck here for while now.
Best Answer
To get one row per day,
The pattern
SUM(boolean)
is a way to count the number of rows where "boolean" is TRUE.This does all the work in a single pass over the data.