Mysql – How to find the same salaries and department names

aliasMySQLsubquery

Write a query to display last name ,department number,and salary of any
employee whose department number and salary both match the department number and salary of any employee using the following table :

employee_id int,
first_name varchar(20),
last_name varchar(25) not null,
email varchar(25) not null,
phone_number varchar(20),
hire_date date not null,
job_id varchar(10) not null,
salary float,
commission_pct float,
manager_id int,
department_id int,
constraint emp_pk primary key(employee_id)

I have tried this :

SELECT * FROM employees e1
WHERE e1.employee_id = ( SELECT employee_id
                           FROM employees e2
          WHERE e2.department_id = e1.department_id 
          AND e2.salary = e1.salary);

What is wrong?

Best Answer

This should work:

select e1.* 
  from employees e1 inner join (
    select count(employee_id) as CNT, department_id, salary 
    from employees group by departmant_id, salary) t1 
  on e1.department_id=t1.department_id and e1.salary=t1.salary 
  where t1.CNT>1

The problem with your own query is twofold:

  • the return value of (select...from ..e2..) is from the very nature of your problem not unique, so the "=" relationship should either throw an error or return whichever is the first result (I'm not familiar enough with MySQL to know which applies), which doesn't have to be the one you're looking for.

  • filtering via "e1.employee_id =" will only ever be true for the record itself, but NOT for another record that matches your criteria

If you insist on using a filter:

SELECT * FROM employees e1
WHERE (e1.department_id,e1.salary) IN 
 (SELECT e2.department_id,e2.salary
  FROM employees e2
  WHERE e2.employee_id <> e1.employee_id)
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