Trying to create a table with the script below. Every time I execute it I get the following error and can't work out why?!
#1064 – You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ') ,
CONSTRAINT cat_id
FOREIGN KEY ()
REFERENCES waitron
.`catego' at line 7 **
CREATE TABLE IF NOT EXISTS `waitron`.`dishes` (
`dish_id` INT NOT NULL AUTO_INCREMENT ,
`dish_name` VARCHAR(90) NULL ,
`dish_desc` VARCHAR(200) NULL ,
`price` DECIMAL(19,4) NULL ,
PRIMARY KEY (`dish_id`) ,
INDEX `cat_id` () ,
CONSTRAINT `cat_id`
FOREIGN KEY ()
REFERENCES `waitron`.`categories` ()
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB;
Best Answer
The index you have named
cat_id
doesn't have any columns in it. You must actually index something in your index. TheFOREIGN KEY ()
column list is also empty. You must actual point at some foreign keys.