A full backup in SQL Server 2008 does not break the log chain. It only resets the differential base-lsn.
You also can restore log backups after restoring from a copy only. The following script demos that:
CREATE DATABASE BakTst13;
GO
ALTER DATABASE BakTst13 SET RECOVERY FULL;
GO
USE BakTst13;
GO
CREATE TABLE dbo.tst(id INT IDENTITY(1,1));
GO
INSERT INTO dbo.tst DEFAULT VALUES
GO 10
GO
BACKUP DATABASE BakTst13
TO DISK = 'BakTst13_Full_1' WITH INIT,FORMAT;
GO
INSERT INTO dbo.tst DEFAULT VALUES
GO 10
GO
BACKUP LOG BakTst13
TO DISK = 'BakTst13_Log_1' WITH INIT,FORMAT;
GO
INSERT INTO dbo.tst DEFAULT VALUES
GO 10
GO
BACKUP DATABASE BakTst13
TO DISK = 'BakTst13_Full_2' WITH INIT,FORMAT;
GO
INSERT INTO dbo.tst DEFAULT VALUES
GO 10
GO
BACKUP DATABASE BakTst13
TO DISK = 'BakTst13_Full_C' WITH COPY_ONLY,INIT,FORMAT;
GO
INSERT INTO dbo.tst DEFAULT VALUES
GO 10
GO
BACKUP LOG BakTst13
TO DISK = 'BakTst13_Log_2' WITH INIT,FORMAT;
GO
USE tempdb;
GO
DROP DATABASE BakTst13;
GO
RESTORE DATABASE BakTst13 FROM DISK='BakTst13_Full_1' WITH NORECOVERY;
RESTORE LOG BakTst13 FROM DISK='BakTst13_Log_1' WITH NORECOVERY;
RESTORE LOG BakTst13 FROM DISK='BakTst13_Log_2' WITH RECOVERY;
GO
SELECT * FROM BakTst13.dbo.tst;
GO
DROP DATABASE BakTst13;
GO
RESTORE DATABASE BakTst13 FROM DISK='BakTst13_Full_C' WITH NORECOVERY;
RESTORE LOG BakTst13 FROM DISK='BakTst13_Log_2' WITH RECOVERY;
GO
SELECT * FROM BakTst13.dbo.tst;
GO
DROP DATABASE BakTst13;
It creates a database and a table and inserts 50 rows into that table. In between those inserts several backups are taken in this order:
- Full
- Log
- Full
- Full Copy_Only
- Log
Next the database is dropped and restored like this:
- 1st Full
- 1st Log
- 2nd Log
The following SELECT
demonstrates that the restore was successful.
This shows that neither a COP_ONLY
nor a normal Full Backup break the log chain.
Then the database is dropped again and restored like this:
- Copy_Only Full
- 2nd Log
Afterwards the SELECT
demonstrates success again.
This demonstrates that you can use a COPY_ONLY
full backup as the base of your Log Restore.
Differential tests
I created a DIFFERENTIAL
version too:
CREATE DATABASE BakTst13;
GO
ALTER DATABASE BakTst13 SET RECOVERY FULL;
GO
USE BakTst13;
GO
CREATE TABLE dbo.tst(id INT IDENTITY(1,1));
GO
INSERT INTO dbo.tst DEFAULT VALUES
GO 10
GO
BACKUP DATABASE BakTst13
TO DISK = 'BakTst13_Full_1' WITH INIT,FORMAT;
GO
INSERT INTO dbo.tst DEFAULT VALUES
GO 10
GO
BACKUP DATABASE BakTst13
TO DISK = 'BakTst13_Diff_1' WITH DIFFERENTIAL,INIT,FORMAT;
GO
INSERT INTO dbo.tst DEFAULT VALUES
GO 10
GO
BACKUP DATABASE BakTst13
TO DISK = 'BakTst13_Full_2' WITH INIT,FORMAT;
GO
INSERT INTO dbo.tst DEFAULT VALUES
GO 10
GO
BACKUP DATABASE BakTst13
TO DISK = 'BakTst13_Diff_2' WITH DIFFERENTIAL,INIT,FORMAT;
GO
INSERT INTO dbo.tst DEFAULT VALUES
GO 10
GO
BACKUP DATABASE BakTst13
TO DISK = 'BakTst13_Full_C' WITH COPY_ONLY,INIT,FORMAT;
GO
INSERT INTO dbo.tst DEFAULT VALUES
GO 10
GO
BACKUP DATABASE BakTst13
TO DISK = 'BakTst13_Diff_3' WITH DIFFERENTIAL,INIT,FORMAT;
GO
USE tempdb;
GO
DROP DATABASE BakTst13;
GO
RAISERROR('------> Starting restore F1, D1, D2',0,1)WITH NOWAIT;
RESTORE DATABASE BakTst13 FROM DISK='BakTst13_Full_1' WITH NORECOVERY;
RESTORE DATABASE BakTst13 FROM DISK='BakTst13_Diff_1' WITH NORECOVERY;
RESTORE DATABASE BakTst13 FROM DISK='BakTst13_Diff_2' WITH NORECOVERY;--<--Fails!
GO
DROP DATABASE BakTst13;
GO
RAISERROR('------> Starting restore FC, D3',0,1)WITH NOWAIT;
RESTORE DATABASE BakTst13 FROM DISK='BakTst13_Full_C' WITH NORECOVERY;
RESTORE DATABASE BakTst13 FROM DISK='BakTst13_Diff_3' WITH NORECOVERY;--<--Fails!
GO
DROP DATABASE BakTst13;
GO
RAISERROR('------> Starting restore F2, D2, D3',0,1)WITH NOWAIT;
RESTORE DATABASE BakTst13 FROM DISK='BakTst13_Full_2' WITH NORECOVERY;
RESTORE DATABASE BakTst13 FROM DISK='BakTst13_Diff_2' WITH NORECOVERY;
RESTORE DATABASE BakTst13 FROM DISK='BakTst13_Diff_3' WITH RECOVERY;
GO
SELECT * FROM BakTst13.dbo.tst;
GO
DROP DATABASE BakTst13;
This takes backups in this order:
- 1st Full
- 1st Differential
- 2nd Full
- 2nd Differential
- Copy_Only Diff
- 3rd Differential
It then tries this restore route:
- 1st Full
- 1st Differential
- 2nd Differential
Step 3 fails with this error:
Msg 3136, Level 16, State 1, Line 4
This differential backup cannot be restored because the database has not been restored to the correct earlier state.
This shows that a normal full backup breaks the differential chain.
Next the database is dropped and this restore flow is attempted:
- Copy_Only Full
- 3rd Differential
Step 2 fails with the same error as step 3 above. This shows that a copy only backup cannot be used as the base for a differential restore.
Then the database is dropped again and the following restore is executed:
- 2nd Full
- 2nd Differential
- 3rd Differential
The following select proves that this restore succeeded. This shows that a COPY_ONLY
Full backup does not interrupt the differential chain.
Best Answer
Full backup is not showing up because it has already been restored and no new latest info is there in msdb to reflect the same. Moreover, once msdb is updated with the backup info, it lets you avail with such info and in a manner of chain as followed in as LSN.
However, you can do this manually by running below script on a specific database to retrieve backup information for. The process will then find the latest Full backup and all transaction log backups that have occurred after this full backup.
Also, you can go through the link here for more option to get the same.