Sql-server – Remove string after second specific character occures from left

Unicode files should have BOM, is the recommended and accepted way, specially for LE:

In UTF-16, a BOM (U+FEFF) may be placed as the first character of a file or character stream to indicate the endianness (byte order) of all the 16-bit code units of the file or stream. If the 16-bit units are represented in big-endian byte order, this BOM character will appear in the sequence of bytes as 0xFE followed by 0xFF. This sequence appears as the ISO-8859-1 characters þÿ in a text display that expects the text to be ISO-8859-1.
...
"The UTF-16 encoding scheme may or may not begin with a BOM. However, when there is no BOM, and in the absence of a higher-level protocol, the byte order of the UTF-16 encoding scheme is big-endian."

'linux' is a very generic term. You must be using some application for processing, and if the application is not recognizing the BOM it means is a bad application. Ditch it for something better.

OK, here is a cheap way, but it is not what I really want (I really want nice charts and graphs!):

-- First PASS
DECLARE @First BIGINT
DECLARE @Second BIGINT
SELECT @First = USER_SEEKS
FROM sys.dm_db_index_usage_stats
where object_id=14473333 AND index_id = 1

WAITFOR DELAY '00:00:15'

SELECT @Second = USER_SEEKS
FROM sys.dm_db_index_usage_stats
where object_id=14473333 AND index_id = 1
SELECT (@Second - @First) 'TableSeeks'
GO