Sql-server – Query To Return Data From MAX(ID)

sql serversql server 2014t-sql

I need to return only the 1 row of the MAX(ID), but my query is not returning such.

This is the result set that I get returned

id      bbid    indate      st  val
200817  16543   01/01/16    1   65.4
2017    16543   01/01/16    1   36.52
1995    16543   01/01/16    1   18.51
20932   1234    03/01/16    1   55.3
22324   1234    03/01/16    1   16.52
55      8232    05/01/16    2   100

This is what I WANT returned

id      bbid    indate      st  val
200817  16543   01/01/16    1   65.4
22324   1234    03/01/16    1   16.52
55      8232    05/01/16    2   100

(Only one row per bbid, and if bbid has multiple entries then pull the data from MAX(ID))

Here is sample DDL to help troubleshoot

Create Table #One
(
  id int
  ,bbid int
  ,val varchar(100)
)

Create Table #Two
(
  bbid int
  ,st int
  ,indate datetime
)

Insert Into #One Values
('200817','16543','65.40')
,('2017','16543','36.52')
,('1995','16543','18.51')
,('20932', '1234', '55.30')
,('22324', '1234', '16.52')
,('55', '8232', '100')

Insert Into #Two Values
('16543', '1', '2016-01-01')
,('1234', '1', '2016-03-01')
,('8232','2', '2016-05-01')

And this is the query I wrote that produced the incorrect results…

Select 
t1.id
,t3.bbid
,t3.indate
,t3.st
,t1.val
FROM #One t1
JOIN 
(
    Select
    id
    ,MAX(ID) As "Maxid"
    FROM #One
    GROUP BY ID
 ) t2
ON t1.id=t2.Maxid
INNER JOIN #Two t3
ON t1.bbid = t3.bbid

How should this query be altered to return my desired result set'?

Best Answer

You can use a common table expression (cte).

;with cte as (
select
     row_number() over(partition by bbid order by #one.id desc) as rn ,id from #one
)
select 
    t1.id
    ,t3.bbid
    ,t3.indate
    ,t3.st
    ,t1.val
from
    #One as t1
join #Two as t3
    on t1.bbid = t3.bbid
join cte
    on cte.id = t1.id
    and cte.rn = 1
order by t1.id desc

Related Solutions

Sql-server – How to return data from a table where the data is the max date of the previous month’s data submissions (-1 of current date)

Expanding on James' answer

Try this code on SqlFiddle.

Also check out @SqlKiwi Paul White's post regarding Delete vs Truncate

create table tracker_live (
  client_nbr int not null, tracker_date date not null, submit_date date not null, live float not null, retainer float not null, bonus float not null
  , constraint pk_tracker_live primary key (client_nbr, tracker_date, submit_date));

insert into tracker_live (client_nbr, tracker_date, submit_date, live, retainer, bonus) values
   (9,'2014-10-01','2014-10-08',537841.5657,1,1)
  ,(9,'2014-11-01','2014-10-08',890293.714,2,2)
  ,(9,'2014-12-01','2014-10-08',45585.4029,3,3)
  ,(9,'2014-10-01','2014-10-17',537841.5657,1,1)
  ,(9,'2014-11-01','2014-10-17',890293.714,2,2)
  ,(9,'2014-12-01','2014-10-17',45585.4029,3,3)
  ,(9,'2014-10-01','2014-11-13',2321938.59,1,1)
  ,(9,'2014-11-01','2014-11-13',907925.1072,2,2)
  ,(9,'2014-12-01','2014-11-13',392917.5237,3,3)
  ,(9,'2014-10-01','2014-11-18',2321938.59,1,1)
  ,(9,'2014-11-01','2014-11-18',795725.1072,2,2)
  ,(9,'2014-12-01','2014-11-18',725835.0474,3,3)

create table tracker_live_last_month (
  client_nbr int not null, tracker_date date not null, submit_date date not null, live float not null, retainer float not null, bonus float not null
  , constraint pk_tracker_live_last_month primary key (client_nbr, tracker_date));  

/* example query for procedure */


declare @test date;
  set @test = '2014-11-18';
  --set @test = convert(date,getdate());
declare @LastDayOfLastMonth date;
  set @LastDayOfLastMonth  = dateadd(day,-datepart(day,@test),@test);
declare @FirstDayOfLastMonth date;  
  set @FirstDayOfLastMonth = dateadd(day,1-datepart(day,@LastDayOfLastMonth),@LastDayOfLastMonth);

  truncate table tracker_live_last_month;

  /* inserting the data with this combined query should be quicker than creating the table and then updating values */
  insert into tracker_live_last_month (client_nbr, tracker_date, submit_date, live, retainer, bonus)
    select tl.client_nbr, tl.tracker_date, ca.submit_date, ca.live, ca.retainer, ca.bonus
      from tracker_live tl
        cross apply (select top 1 i.submit_date, i.live, i.retainer, i.bonus 
          from tracker_live i 
          where i.client_nbr=tl.client_nbr 
            and i.tracker_date=tl.tracker_date
          order by i.submit_date desc) as ca
      where tl.submit_date between @FirstDayOfLastMonth and @LastDayofLastMonth
      group by tl.client_nbr, tl.tracker_date, ca.submit_date, ca.retainer, ca.live, ca.bonus
      order by tl.client_nbr, tl.tracker_date, ca.submit_date, ca.retainer, ca.live, ca.bonus;

Sql-server – Query to Return Missing Data

You can use SQL's EXCEPT clause. https://msdn.microsoft.com/en-us/library/ms188055.aspx

Values in the first table (the left query) that are not in the second (the right query) will be shown. You can change the table order to achieve the opposite.

select * from @Test1
except
select * from @Test2


card4       d1         amt
----------- ---------- ----------------------
1111        2015-01-01 55.1
2222        2015-01-01 23.12

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