Postgresql – What does @ signify in a query expression

If I understand what you're trying to achieve, then I think what you want is a CTE with a UNION list of all the possible tags you want to compare against, then RIGHT JOIN the tag table against the CTE.

Example -

WITH ListOfTags (Tag) AS (SELECT 'Foo' UNION SELECT 'bar' UNION SELECT 'other' UNION SELECT 'thing')
SELECT  *
FROM    item_tag    i
INNER JOIN  tags    t
    ON i.tag_id = t.tag_id
RIGHT JOIN ListOfTags   l
    ON  l.Tag like t.tag
WHERE   i.item_id is null

This might not be the most elegant way of doing it, but it might work for you

You are forming an ad-hoc row type (effectively an anonymous record) with this expression:

(media_files.position, media_files.token, media_files.title)

in your aggregate function call:

ARRAY_AGG((media_files.position, media_files.token, media_files.title)
          ORDER BY media_files.position) AS media_files

Arrays types can only be built upon well-known types. Your option is to announce such a type to the system and cast the record to it before forming the array. Create a well-known composite type:

CREATE TYPE my_type AS (
  position int    -- data type?
 ,token    text
 ,title    text
 )

I am guessing data types for lack of information here. Fill in your actual types.

Creating a table has the same effect: It announces a well known composite type to the system indirectly, as well. For this reason, you can (ab-)use a temporary table to register a composite type for the duration of the session:

CREATE TEMP TABLE my_type AS (
  position int    -- data type?
 ,token    text
 ,title    text
 )

Either way, you can then cast your record:

ARRAY_AGG((media_files.position, media_files.token, media_files.title)::my_type
          ORDER BY media_files.position) AS media_files

Then you can reference elements of the (now well-known) type by name:

SELECT media_files[1].position, media_files[1].token
FROM  (
     ...
   ,ARRAY_AGG((media_files.position, media_files.token, media_files.title)::my_type
          ORDER BY media_files.position) AS media_files
   ...
   FROM ....
   GROUP BY ...
  ) sub;

Now, Postgres can use these names for building a JSON value. Voilá.