There are a few problems with your tables. I'll try to address the foreign keys first, since you question asked about them :)
But before that, we should realize that the two sets of tables (the first three you created and the second set, which you created after dropping the first set) are the same. Of course, the definition of Table3
in your second attempt has syntax and logical errors, but the basic idea is:
CREATE TABLE table3 (
"ID" bigint NOT NULL DEFAULT '0',
"DataID" bigint DEFAULT NULL,
"Address" numeric(20) DEFAULT NULL,
"Data" bigint DEFAULT NULL,
PRIMARY KEY ("ID"),
FOREIGN KEY ("DataID") REFERENCES Table1("DataID") on delete cascade on update cascade,
FOREIGN KEY ("Address") REFERENCES Table2("Address") on delete cascade on update cascade
);
This definition tell PostgreSQL roughly the following: "Create a table with four columns, one will be the primary key (PK), the others can be NULL
. If a new row is inserted, check DataID
and Address
: if they contain a non-NULL value (say 27856), then check Table1
for DataID
Λ™and Table2
for Address
. If there is no such value in those tables, then return an error." This last point which you've seen first:
ERROR: insert or update on table "Table3" violates foreign key constraint
"Table3_DataID_fkey" DETAIL: Key (DataID)=(27856) is not present in table "Table1".
So simple: if there is no row in Table1
where DataID = 27856
, then you can't insert that row into Table3
.
If you need that row, you should first insert a row into Table1
with DataID = 27856
, and only then try to insert into Table3
. If this seems to you not what you want, please describe in a few sentences what you want to achieve, and we can help with a good design.
And now about the other problems.
You define your PKs as
CREATE all_your_tables (
first_column NOT NULL DEFAULT '0',
[...]
PRIMARY KEY ("ID"),
A primary key means that all the items in it are different from each other, that is, the values are UNIQUE
. If you give a static DEFAULT
(like '0'
) to a UNIQUE
column, you will experience bad surprises all the time. This is what you got in your third error message.
Furthermore, '0'
means a text string, but not a number (bigint
or numeric
in your case). Use simply 0
instead (or don't use it at all, as I written above).
And a last point (I may be wrong here): in Table2
, your Address
field is set to numeric(20)
. At the same time, it is the PK of the table. The column name and the data type suggests that this address can change in the future. If this is true, than it is a very bad choice for a PK. Think about the following scenario: you have an address '1234567890454', which has a child in Table3
like
ID DataID Address Data
123 3216547 1234567890454 654897564134569
Now that address happens to change to something other. How do you make your child row in Table3
follow its parent to the new address? (There are solutions for this, but can cause much confusion.) If this is your case, add an ID column to your table, which will not contain any information from the real world, it will simply serve as an identification value (that is, ID) for an address.
Best Answer
To begin with: for a simple view like that you don't need a rule (at least not in any current Postgres version).
The reason you get that problem is this:
Now if you don't supply value for
mydate
when inserting into the view, thenNEW._date
will benull
, and thus you are trying to put an explicitNULL
value into that column. You need to take that situation into account:Unrelated but: you have another problem in your statement:
"Mozzart"
is a column name, string literals need to be enclosed in single quotes:'Mozzart'
. Postgres should have thrown acolumn "Mozzart" does not exist
error.For details, please see the manual: http://www.postgresql.org/docs/current/static/sql-syntax-lexical.html#SQL-SYNTAX-CONSTANTS
Finally: your view definition is wrong:
selects a single column that is an anonymous structure with two elements. You need to get rid of those useless parentheses, the
CREATE VIEW
should have thrown an errorCREATE VIEW specifies more column names than columns
.You need to use: