PostgreSQL – Optimal Query to Show Active Records by Date

WHERE playable_character = 0 AND
    date_published BETWEEN date_sub(now(), INTERVAL 3 YEAR) AND now()

Start with the "=" item, then do the range:

INDEX(playable_character, date_published);

"Pagination", a la ORDER BY rating DESC LIMIT 4000, 1000; is best done by remember where you "left off". That way, you don't have scan over the 4000 records that you don't need.

Core feature is the window function lag().
Also pay special attention to avoid deadlocks and race conditions with concurrent deletes and inserts (which can affect which rows to delete!):

CREATE OR REPLACE FUNCTION remove_vendor_price_dupes(_vendor int)
  RETURNS integer AS
$func$
DECLARE
   del_ct int;
BEGIN
   -- this may or may not be necessary:
   -- lock rows to avoid race conditions with concurrent deletes
   PERFORM 1
   FROM   vendor_prices
   WHERE  vendor = _vendor
   ORDER  BY sku, effective_date, id  -- guarantee row locks in consistent order
   FOR    UPDATE;

   -- delete redundant prices
   DELETE FROM vendor_prices v
   USING (
      SELECT id
           , price = lag(price) OVER w  -- same as last row
             AND (lead(id) OVER w) IS NOT NULL AS del  -- not last row
      FROM   vendor_prices
      WHERE  vendor = _vendor
      WINDOW w AS (PARTITION BY sku ORDER BY effective_date, id)
      ) d
   WHERE v.id = d.id
   AND   d.del;

   GET DIAGNOSTICS del_ct = ROW_COUNT;  -- optional:
   RETURN del_ct;  -- return number of deleted rows
END
$func$  LANGUAGE plpgsql;

Call:

SELECT remove_vendor_price_dupes(1);

Notes

• The current version of the 9.3 major release is 9.3.6. The project recommends that ...

  all users run the latest available minor release for whatever major version is in use.

• A multicolumn index on (vendor, sku, effective_date, id) would be perfect for this - in this particular order. But Postgres can combine indexes rather efficiently, too.
  It might pay to add the otherwise irrelevant price as last item ot the index to get index-only scans out of this. You'll have to test.

• Since you have concurrent deletes it may be a good idea to run a separate delete per vendor to reduce the potential for race conditions and deadlocks. Since there are only a few vendors, this seems like a reasonable partitioning. (Many tiny calls would be comparatively slow.)

• I am running a separate SELECT (PERFORM in plpgsql, since we do not use the result) because the row locking clause FOR UPDATE cannot be used together with window functions. Don't let the keyword mislead you, this is not just for updates. I am locking all rows for the given vendor, since the result depends on all rows. Concurrent reads are not impaired, only concurrent writes have to wait until we are done. That's another reason why deleting rows for one vendor at a time in a separate transaction should be best.

• sku is unique per product, so we can PARTITION BY it.

• ORDER BY effective_date, id: your first version of the question included code for duplicate rows, so I added id to ORDER BY as additional tie breaker. This way it works for duplicates on (sku, effective_date) as well.

• To preserve the last row for each set: AND (lead(id) OVER w) IS NOT NULL. Reusing the same window for lead() is cheap - independent of the added explicit WINDOW clause - that's just syntax shorthand for convenience.

• I am locking rows in the same order: ORDER BY sku, effective_date, id. Make sure that concurrent DELETEs operate in the same order to avoid deadlocks. If all other transactions delete no more than a single row within the same transaction, there cannot be deadlocks and you don't need the row locking at all.

• If concurrent INSERTs could lead to a different result (make different rows obsolete), you have to lock the whole table in EXCLUSIVE mode instead to avoid race conditions:

  LOCK TABLE vendor_prices IN EXCLUSIVE MODE;
  

  Do that only if it's necessary. It blocks all concurrent write access.

• I am returning the number of rows deleted, but that's totally optional. You might as well return nothing and declare the function as RETURNS void.