Postgresql function to create table

functionsplpgsqlpostgresqlpostgresql-9.2

I want to create a function in order to create a table with a specific structure pasing part of the name of the table as an argument so the name of the table is t_ . Similar to this:

CREATE OR REPLACE FUNCTION create_table_type1(t_name VARCHAR(30)) RETURNS VOID AS $$
BEGIN
    EXECUTE "CREATE TABLE IF NOT EXISTS t_"|| t_name ||"
    (
    id SERIAL,
    customerid INT,
    daterecorded DATE,
            value DOUBLE PRECISION,
    PRIMARY KEY (id)
    )"
END
$$ LANGUAGE plpgsql

Then call it like:

SELECT create_table_type1('one');

Is it possible?

Best Answer

Answer is yes. :)

CREATE OR REPLACE FUNCTION create_table_type1(t_name varchar(30))
  RETURNS VOID
  LANGUAGE plpgsql AS
$func$
BEGIN
   EXECUTE format('
      CREATE TABLE IF NOT EXISTS %I (
       id serial PRIMARY KEY,
       customerid int,
       daterecorded date,
       value double precision
      )', 't_' || t_name);
END
$func$;

I am using format() with %I to sanitize the table name and avoid SQL injection. Requires PostgreSQL 9.1 or above.

Be sure to use single quotes ('') for data. Double quotes ("") are for identifiers in SQL.

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