Postgresql – Count rows for each latest status of tickets

You can use conditional sum for this calculation something as

select 
date_format(created,'%d-%m') as created_date , 
sum( case when status='open' then 1 else 0 end )+
sum( case when status='new' then 1 else 0 end )+
sum( case when status='resolved' and date(resolved) > date(created) then 1 else 0 end ) as open
from table_name
where
YEAR(Created) = '2015'
group by created_date ;

Here is a test case

mysql> select * from test ;
+------+---------------------+---------------------+----------+
| id   | created             | resolved            | status   |
+------+---------------------+---------------------+----------+
|    1 | 2015-05-10 00:00:00 | 1970-01-01 00:00:00 | open     |
|    2 | 2015-05-10 00:00:00 | 1970-01-01 00:00:00 | new      |
|    3 | 2015-05-10 00:00:00 | 2015-05-12 00:00:00 | resolved |
|    4 | 2015-05-11 00:00:00 | 1970-01-01 00:00:00 | open     |
|    5 | 2015-05-11 00:00:00 | 1970-01-01 00:00:00 | new      |
|    6 | 2015-05-11 00:00:00 | 2015-05-11 00:00:00 | resolved |
+------+---------------------+---------------------+----------+
6 rows in set (0.00 sec)

mysql> select 
    -> date_format(created,'%d-%m') as created_date , 
    -> sum( case when status='open' then 1 else 0 end )+
    -> sum( case when status='new' then 1 else 0 end )+
    -> sum( case when status='resolved' and date(resolved) > date(created) then 1 else 0 end ) as open
    -> from test
    -> where
    -> YEAR(Created) = '2015'
    -> group by created_date ;
+--------------+------+
| created_date | open |
+--------------+------+
| 10-05        |    3 |
| 11-05        |    2 |
+--------------+------+
2 rows in set (0.00 sec)

UPDATE The count of open is a incremental as per the comment. So the following should do the trick

select
created_date,
@open:= @open+open_ticket-resolved as open
from(
 select 
 date_format(created,'%d-%m') as created_date , 
 sum( case when status='open' then 1 else 0 end )+
 sum( case when status='new' then 1 else 0 end )+
 sum( case when status='resolved' and ( date(resolved) > date(created) or date(resolved) = date(created)) then 1 else 0 end ) as open_ticket,
 sum(case when status = 'resolved' and date(resolved) = date(created) then 1 else 0 end) as resolved
 from test
 where
 YEAR(Created) = '2015'
 group by created_date
)x,(select @open:=0)r order by created_date ; 

From the above sample data it will have

 +--------------+------+
| created_date | open |
+--------------+------+
| 10-05        |    3 |
| 11-05        |    5 |
+--------------+------+

UPDATE:

Count the previous tickets which got resolved on a given date and deduct that from the current day open ticket, for that you need a left join something as

select
created_date,
@open:= @open+open_ticket-resolved_ticket as open
from(
 select 
 date_format(t.created,'%d-%m') as created_date , 
 sum( case when t.status='open' then 1 else 0 end )+
 sum( case when t.status='new' then 1 else 0 end )+
 sum( case when t.status='resolved' and ( date(t.resolved) > date(created) or date(t.resolved) = date(created)) then 1 else 0 end ) as open_ticket,
 coalesce(tot,0) as resolved_ticket
 from test t left join(
    select count(*) as tot, date(resolved) as resolved from test where status='resolved' group by date(resolved)
 )x on date(x.resolved) = date(t.created) 
 where
 YEAR(t.created) = '2015'
 group by created_date
)x,(select @open:=0)r order by created_date ; 

OUTPUT :

+--------------+------+
| created_date | open |
+--------------+------+
| 10-05        |    3 |
| 11-05        |    5 |
| 12-05        |    7 |
+--------------+------+

Given this sample data:

CREATE TABLE #d ( column1 char(2), column2 varchar(32) );

INSERT #d (column1, column2) 
   VALUES ('x1',    'temp/page1_l'),
          ('x1',    'temp/page2_f'),
          ('x2',    'temp/page2_d'),
          ('x2',    'temp/page1_k'),
          ('x2',    'temp/page2_e');

One way to solve it is by taking the count separately:

;WITH agg AS
(
  SELECT column1, col1count = COUNT(*)
    FROM #d 
    GROUP BY column1
)
SELECT [count(column1)] = agg.col1count, filt.column2
  FROM agg INNER JOIN #d AS filt
    ON agg.column1 = filt.column1
  WHERE filt.column2 LIKE '%page1[_]%';

Or slightly differently:

;WITH d AS
(
  SELECT column1, column2, 
    column1count = COUNT(*) OVER (PARTITION BY column1)
  FROM #d
)
SELECT [count(column1)] = column1count, column2 
  FROM d
  WHERE column2 LIKE '%page1[_]%';

Another is along the lines of Rob's suggestion:

SELECT [count(column1)] = COUNT(column1),
    column2 = MIN(CASE WHEN column2 LIKE '%page1[_]%' THEN column2 END)
  FROM #d 
  GROUP BY column1;