Your additional calculated value:
(select count(t1.num) from T t1)
Is a scalar subquery, which is a dynamic rather than static expression. As such it's treated the same as a column as far as the aggregate is concerned and needs to be included in the group by clause to avoid the ORA-00937: not a single-group group function
error
However, oracle does not allow subqueries as part of the group by clause and trying to include the scalar subquery and/or the whole case statement:
group by (case (select count(*) cnt from t t1) when 0 then 1 else 0 end)
just results in an ORA-22818: subquery expressions not allowed here
error.
The only ways around this are to either convert your scalar subquery to an aggregate value like so:
max(case (select count(*) cnt from t t1) when 0 then 1 else 0 end)
or
(case max((select count(*) cnt from t t1)) when 0 then 1 else 0 end)
or rewrite your query to move the unaggregated scalar subquery out of the aggregated query:
select (case (select count(*) cnt from t t1) when 0 then 1 else 0 end) * sum
from (select sum(t3.num) sum from t t3) t2;
or precompute your scalar subquery so it can be used in the group by clause:
select case t1.cnt when 0 then 1 else 0 end * sum(t2.num)
from t t2
, (select count(*) cnt from t) t1
group by case t1.cnt when 0 then 1 else 0 end
Best Answer
In Oracle you can have your own aggregation function. To write one, we need to implement an interface which looks like this:
The above is just the type definition introducing the type with the required type interface amended by a field definition which stores the value aggregated so far.
This interface can be implemented as follows:
Now that the datatype is defined completely, we need to generate a stub function which can be used as an aggregating function in a select-statement:
I chose the name
agg_product
, but feel free to choose any name you prefer or like best. As an example of how this can be used in your case, try: