Because you granted it access without password...
If a user has no password, logging in with one will always fail.
Set the password for user, only then you'll be able to use -p
In addition, you might want to remove the Any user.
The problem I see with what you propose is that a user who has the ability to grant privileges to other users... is, almost by definition, not a "limited" user.
You can't grant privileges at all without the GRANT privilege, and even with that, you can't grant a specific privilege that you don't possess ... unless you have permission to manipulate the grant tables directly, in which case, you're not exactly a limited user either.
But, aha, here's your workaround.
Stored procedures run with the credentials of the user who defined them or as the explicitly-specified definer. (You have to have SUPER to specify somebody else as DEFINER.) Any user with the EXECUTE privilege on a stored procedure can execute the procedure, and the procedure essentially escalates their privilege level while it is running.
If you wrap your administrative operations in (well-written) procedures, then you don't have to actually give the limited user permission to do anything, other than run the procedures.
DELIMITER $$
DROP PROCEDURE IF EXISTS `mysql`.`change_password` $$
-- root@localhost is an example; use an appropriate local user that has the
-- permissions that need to be available for the operation to succeed
CREATE DEFINER='root'@'localhost' PROCEDURE `mysql`.`change_password` (
IN dirty_user VARCHAR(16),
IN dirty_host VARCHAR(40),
IN dirty_password VARCHAR(41))
BEGIN
DECLARE encrypted_password TINYTEXT DEFAULT PASSWORD(dirty_password);
DECLARE clean_user TINYTEXT DEFAULT NULL;
DECLARE clean_host TINYTEXT DEFAULT NULL;
SELECT user, host
FROM mysql.user
WHERE user = dirty_user
AND host = dirty_host
INTO clean_user, clean_host;
IF clean_user IS NULL OR clean_host IS NULL THEN
SIGNAL SQLSTATE '45000' SET MESSAGE_TEXT = 'user/host provided does not exist';
END IF;
SET @_sql = CONCAT_WS('\'','SET PASSWORD FOR ',clean_user,'@',clean_host,' = ',encrypted_password,'');
PREPARE stmt FROM @_sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
SET @_sql = NULL;
END $$
DELIMITER ;
GRANT EXECUTE ON PROCEDURE mysql.change_password TO 'limited'@'%';
The 'limited'@'%' user can now change passwords for other users even though they don't have permission to do it themselves, by using CALL mysql.change_password('user','host','password');.
This user does not have permissions themselves, but does have execute on the proc; they can't do it directly:
mysql> set password for 'wombat'@'localhost' = PASSWORD('secret');
ERROR 1044 (42000): Access denied for user 'limited'@'%' to database 'mysql'
... but they can do it this way. Note that "0 rows affected" is not a meaningful value.
mysql> call mysql.change_password('wombat','localhost','secret');
Query OK, 0 rows affected (0.00 sec)
Notes:
String-concatenated queries with input parameters are unacceptable, but the SET PASSWORD statement does not accept ? positional-parameters, so there's no choice here. To sanitize the inputs, I take care of the password by encrypting it in advance, outside the prepared statement, and concatenated the encrypted password there; I've sanitized the user and host by actually selecting them from the mysql.user table and using the values I've selected, also outside the prepared statement. If they aren't found, we can't set their password, so we throw an exception using SIGNAL. If they are found, we concatenate the fetched values into the prepared statement, sanitizing them by this mechanism. It's still theoretically possible that bad data in the mysql.user table could render the quoting of the prepared statement invalid, but if you have bad data in the mysql.user table, then you have 2 problems (1 problem in addition to this one).
Any explicit GRANT EXECUTE you've given at the procedure level disappears from the mysql.procs_priv table if you drop and redefine the procedure, so if you make changes to the procedure, you have to re-grant the privileges to the limited user.
You need MySQL 5.5+ for the SIGNAL statement to be valid. Below 5.5 you can replace it with a hack, something like CALL mysql.`change_password(): the user/host provided`; (note the backticks) which will throw a not quite as pretty, but still serviceable message complaining that the bogus procedure name quoted in the backticks... does not exist. Heh... ERROR 1305 (42000): PROCEDURE mysql.change_password(): the user/host provided does not exist
Best Answer
It is the way MySQL authenticates and current users installed.
When you run this command
you quickly learn that USER() tells you how mysqld sees you trying to login and CURRENT_USER() tells you how mysqld allowed you to login. I discussed this 3 years ago in Why does OS login not exist in the user table, but I can still login to MySQL?
My guess is that whatever CURRENT_USER() is in mysql.user has no password.
You can run
SELECT CONCAT(QUOTE(user),QUOTE(host)) userhost,password FROM mysql.user;to see your users. You might note that password is blank.To solve your issue, you must create a remote username and password.