I personally would use a model similar to the following:
The product table would be pretty basic, your main product details:
create table product
(
part_number int, (PK)
name varchar(10),
price int
);
insert into product values
(1, 'product1', 50),
(2, 'product2', 95.99);
Second the attribute table to store the each of the different attributes.
create table attribute
(
attributeid int, (PK)
attribute_name varchar(10),
attribute_value varchar(50)
);
insert into attribute values
(1, 'color', 'red'),
(2, 'color', 'blue'),
(3, 'material', 'chrome'),
(4, 'material', 'plastic'),
(5, 'color', 'yellow'),
(6, 'size', 'x-large');
Finally create the product_attribute table as the JOIN table between each product and its attributes associated with it.
create table product_attribute
(
part_number int, (FK)
attributeid int (FK)
);
insert into product_attribute values
(1, 1),
(1, 3),
(2, 6),
(2, 2),
(2, 6);
Depending on how you want to use the data you are looking at two joins:
select *
from product p
left join product_attribute t
on p.part_number = t.part_number
left join attribute a
on t.attributeid = a.attributeid;
See SQL Fiddle with Demo. This returns data in the format:
PART_NUMBER | NAME | PRICE | ATTRIBUTEID | ATTRIBUTE_NAME | ATTRIBUTE_VALUE
___________________________________________________________________________
1 | product1 | 50 | 1 | color | red
1 | product1 | 50 | 3 | material | chrome
2 | product2 | 96 | 6 | size | x-large
2 | product2 | 96 | 2 | color | blue
2 | product2 | 96 | 6 | size | x-large
But if you want to return the data in a PIVOT
format where you have one row with all of the attributes as columns, you can use CASE
statements with an aggregate:
SELECT p.part_number,
p.name,
p.price,
MAX(IF(a.ATTRIBUTE_NAME = 'color', a.ATTRIBUTE_VALUE, null)) as color,
MAX(IF(a.ATTRIBUTE_NAME = 'material', a.ATTRIBUTE_VALUE, null)) as material,
MAX(IF(a.ATTRIBUTE_NAME = 'size', a.ATTRIBUTE_VALUE, null)) as size
from product p
left join product_attribute t
on p.part_number = t.part_number
left join attribute a
on t.attributeid = a.attributeid
group by p.part_number, p.name, p.price;
See SQL Fiddle with Demo. Data is returned in the format:
PART_NUMBER | NAME | PRICE | COLOR | MATERIAL | SIZE
_________________________________________________________________
1 | product1 | 50 | red | chrome | null
2 | product2 | 96 | blue | null | x-large
As you case see the data might be in a better format for you, but if you have an unknown number of attributes, it will easily become untenable due to hard-coding attribute names, so in MySQL you can use prepared statements to create dynamic pivots. Your code would be as follows (See SQL Fiddle With Demo):
SET @sql = NULL;
SELECT
GROUP_CONCAT(DISTINCT
CONCAT(
'MAX(IF(a.attribute_name = ''',
attribute_name,
''', a.attribute_value, NULL)) AS ',
attribute_name
)
) INTO @sql
FROM attribute;
SET @sql = CONCAT('SELECT p.part_number
, p.name
, ', @sql, '
from product p
left join product_attribute t
on p.part_number = t.part_number
left join attribute a
on t.attributeid = a.attributeid
GROUP BY p.part_number
, p.name');
PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
This generates the same result as the second version with no need to hard-code anything. While there are many ways to model this I think this database design is the most flexible.
Your concerns are valid , mysql documentations says
If you access a column from the table to be updated in an expression, UPDATE uses the current value of the column. For example, the following statement sets col1 to one more than its current value:
UPDATE t1 SET col1 = col1 + 1;
The second assignment in the following statement sets col2 to the
current (updated) col1 value, not the original col1 value. The result
is that col1 and col2 have the same value. This behavior differs from
standard SQL.
UPDATE t1 SET col1 = col1 + 1, col2 = col1;
To work it around, I'd suggest adding 2 columns, say homescore_old
and awayscore_old
, copying homescore
and awayscore
there, and then do you UPDATE
using newly added columns on the right side assignment. When it's done, you can drop old
columns. It might also be possible to use just one extra column, but again, documentation states,
Single-table UPDATE assignments are generally evaluated from left to right.
and in my understanding, "generally" is not the same as "always".
Best Answer
These should be wrapped in a transaction using an intermediate value;
Choosing a high end @tmpid namespace to avoid collisions is important not to run into trouble later.