Mysql – SQL Query Self Join

MySQL

How to get the below result set from mysql query. The challenge is everything is just in single table and only way to differentiate one row with another is Date field.

product_id     |   CREATED_STAMP     | PRODUCT_PRICE_PURPOSE_ID | PRICE   | SERIAL_NUMBER

10000000349098 | 2017-01-04 13:11:07 |  Purchase_Price          |   30    |  ytre
10000000349098 | 2017-01-04 13:11:07 |  MRP                     |   50    |  ytre
10000000349098 | 2017-01-04 13:09:43 |  Purchase_Price          |   100   |  gfr
10000000349098 | 2017-01-04 13:09:43 |  MRP                     |   280   |  gfr

Result

 Product Id    |  SN Purchase | Price | MRP | Serial Number | Purchase Price    | MRP

10000000349098 |  gfr         |  100  | 280 | ytre          |  30               | 50

Best Answer

Create a View to retrieve the main record:

CREATE 
  ALGORITHM = UNDEFINED 
  SQL SECURITY DEFINER
VIEW `new_view` AS
SELECT 
    t.*
FROM tablename t
WHERE t.PRODUCT_PRICE_PURPOSE_ID = 'Purchase_Price')
ORDER BY t.CREATED_STAMP
LIMIT 1

Build the query:

SELECT
   t.product_id, t.SERIAL_NUMBER, t.PRICE,
   t_2.PRICE,
   t_3.SERIAL_NUMBER, t_3.PRICE,
   t_4.PRICE
FROM new_view t
  LEFT JOIN tableName t_2 ON t.CREATED_STAMP = t_2.CREATED_STAMP and t.SERIAL_NUMBER = t_2.SERIAL_NUMBER and t_2.PRODUCT_PRICE_PURPOSE_ID = 'MRP'
  LEFT JOIN tableName t_3 ON t.product_id = t_3.product_id and t_3.CREATED_STAMP > t.CREATED_STAMP and t_3.PRODUCT_PRICE_PURPOSE_ID = 'Purchase_Price'
  LEFT JOIN tableName t_4 ON t_3.CREATED_STAMP = t_4.CREATED_STAMP and t_4.SERIAL_NUMBER = t_3.SERIAL_NUMBER and t_4.PRODUCT_PRICE_PURPOSE_ID = 'MRP'
where t.PRODUCT_PRICE_PURPOSE_ID = 'Purchase_Price'

OR in one query

SELECT
   t.product_id, t.SERIAL_NUMBER, t.PRICE,
   t_2.PRICE,
   t_3.SERIAL_NUMBER, t_3.PRICE,
   t_4.PRICE
FROM
 (SELECT * FROM tablename WHERE PRODUCT_PRICE_PURPOSE_ID = 'Purchase_Price'
  ORDER BY CREATED_STAMP LIMIT 1
 ) as t
   LEFT JOIN tableName t_2 ON t.CREATED_STAMP = t_2.CREATED_STAMP and t.SERIAL_NUMBER = t_2.SERIAL_NUMBER and t_2.PRODUCT_PRICE_PURPOSE_ID = 'MRP'
   LEFT JOIN tableName t_3 ON t.product_id = t_3.product_id and t_3.CREATED_STAMP > t.CREATED_STAMP and t_3.PRODUCT_PRICE_PURPOSE_ID = 'Purchase_Price'
   LEFT JOIN tableName t_4 ON t_3.CREATED_STAMP = t_4.CREATED_STAMP and t_4.SERIAL_NUMBER = t_3.SERIAL_NUMBER and t_4.PRODUCT_PRICE_PURPOSE_ID = 'MRP'
WHERE t.PRODUCT_PRICE_PURPOSE_ID = 'Purchase_Price'

Related Solutions

Product Attribute List Design Pattern in MySQL

I personally would use a model similar to the following:

The product table would be pretty basic, your main product details:

create table product
(
  part_number int, (PK)
  name varchar(10),
  price int
);
insert into product values
(1, 'product1', 50),
(2, 'product2', 95.99);

Second the attribute table to store the each of the different attributes.

create table attribute
(
  attributeid int, (PK)
  attribute_name varchar(10),
  attribute_value varchar(50)
);
insert into attribute values
(1, 'color', 'red'),
(2, 'color', 'blue'),
(3, 'material', 'chrome'),
(4, 'material', 'plastic'),
(5, 'color', 'yellow'),
(6, 'size', 'x-large');

Finally create the product_attribute table as the JOIN table between each product and its attributes associated with it.

create table product_attribute
(
  part_number int, (FK)
  attributeid int  (FK) 
);
insert into product_attribute values
(1,  1),
(1,  3),
(2,  6),
(2,  2),
(2,  6);

Depending on how you want to use the data you are looking at two joins:

select *
from product p
left join product_attribute t
  on p.part_number = t.part_number
left join attribute a
  on t.attributeid = a.attributeid;

See SQL Fiddle with Demo. This returns data in the format:

PART_NUMBER | NAME       | PRICE | ATTRIBUTEID | ATTRIBUTE_NAME | ATTRIBUTE_VALUE
___________________________________________________________________________
1           | product1   | 50    | 1           | color          | red
1           | product1   | 50    | 3           | material       | chrome
2           | product2   | 96    | 6           | size           | x-large
2           | product2   | 96    | 2           | color          | blue
2           | product2   | 96    | 6           | size           | x-large

But if you want to return the data in a PIVOT format where you have one row with all of the attributes as columns, you can use CASE statements with an aggregate:

SELECT p.part_number,
  p.name,
  p.price,
  MAX(IF(a.ATTRIBUTE_NAME = 'color', a.ATTRIBUTE_VALUE, null)) as color,
  MAX(IF(a.ATTRIBUTE_NAME = 'material', a.ATTRIBUTE_VALUE, null)) as material,
  MAX(IF(a.ATTRIBUTE_NAME = 'size', a.ATTRIBUTE_VALUE, null)) as size
from product p
left join product_attribute t
  on p.part_number = t.part_number
left join attribute a
  on t.attributeid = a.attributeid
group by p.part_number, p.name, p.price;

See SQL Fiddle with Demo. Data is returned in the format:

PART_NUMBER | NAME       | PRICE | COLOR | MATERIAL | SIZE
_________________________________________________________________
1           | product1   | 50    | red   | chrome   | null
2           | product2   | 96    | blue  | null     | x-large

As you case see the data might be in a better format for you, but if you have an unknown number of attributes, it will easily become untenable due to hard-coding attribute names, so in MySQL you can use prepared statements to create dynamic pivots. Your code would be as follows (See SQL Fiddle With Demo):

SET @sql = NULL;
SELECT
  GROUP_CONCAT(DISTINCT
    CONCAT(
      'MAX(IF(a.attribute_name = ''',
      attribute_name,
      ''', a.attribute_value, NULL)) AS ',
      attribute_name
    )
  ) INTO @sql
FROM attribute;

SET @sql = CONCAT('SELECT p.part_number
                    , p.name
                    , ', @sql, ' 
                   from product p
                   left join product_attribute t
                     on p.part_number = t.part_number
                   left join attribute a
                     on t.attributeid = a.attributeid
                   GROUP BY p.part_number
                    , p.name');

PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;

This generates the same result as the second version with no need to hard-code anything. While there are many ways to model this I think this database design is the most flexible.

MySQL – How to Merge 3 Tables with Conditions

As first step I merge the two product tables. I need an full outer join on product1 and product2 tables. To obtain on outer join in mysql we can union a left join and a right join. Start with a left join. In the following query IFNULL(p1.key1, p2.key1) is useful to merge two key column coming from the two product tables and IFNULL(, 'NaN') is useful to obtain 'NaN' in the output.

select IFNULL(p1.key1, p2.key1) as key1, 
       IFNULL(p1.key2, p2.key2) as key2,
       IFNULL(p1.serial, p2.serial) as serial,
       IFNULL(p1.product_data, 'NaN') as product_data1, 
       IFNULL(p2.product_data, 'NaN') as product_data2
from       product1 p1
left join  product2 p2 on p1.key1 = p2.key1 and p1.key2 = p2.key2 and p1.serial =     p2.serial;

To obtain a full outer join I need to repeat the previous query with 'right join' and union the result with the 'left join'

select IFNULL(p1.key1, p2.key1) as key1, 
       IFNULL(p1.key2, p2.key2) as key2,
       IFNULL(p1.serial, p2.serial) as serial,
       IFNULL(p1.product_data, 'NaN') as product_data1, 
       IFNULL(p2.product_data, 'NaN') as product_data2
from       product1 p1
left join  product2 p2 on p1.key1 = p2.key1 and p1.key2 = p2.key2 and p1.serial = p2.serial
union
select IFNULL(p1.key1, p2.key1) as key1, 
       IFNULL(p1.key2, p2.key2) as key2,
       IFNULL(p1.serial, p2.serial) as serial,
       IFNULL(p1.product_data, 'NaN') as product_data1, 
       IFNULL(p2.product_data, 'NaN') as product_data2
from       product1 p1
right join  product2 p2 on p1.key1 = p2.key1 and p1.key2 = p2.key2 and p1.serial = p2.serial;

For convenience, I create a view with the previous query:

create or replace view p12 as
select IFNULL(p1.key1, p2.key1) as key1, 
       IFNULL(p1.key2, p2.key2) as key2,
       IFNULL(p1.serial, p2.serial) as serial,
       IFNULL(p1.product_data, 'NaN') as product_data1, 
       IFNULL(p2.product_data, 'NaN') as product_data2
from       product1 p1
left join  product2 p2 on p1.key1 = p2.key1 and p1.key2 = p2.key2 and p1.serial = p2.serial
union
select IFNULL(p1.key1, p2.key1) as key1, 
       IFNULL(p1.key2, p2.key2) as key2,
       IFNULL(p1.serial, p2.serial) as serial,
       IFNULL(p1.product_data, 'NaN') as product_data1, 
       IFNULL(p2.product_data, 'NaN') as product_data2
from       product1 p1
right join  product2 p2 on p1.key1 = p2.key1 and p1.key2 = p2.key2 and p1.serial = p2.serial;

To check we can try with:

mysql> select * from p12 where key1 = 1 and key2 =1 ;
+------+------+--------+---------------+---------------+
| key1 | key2 | serial | product_data1 | product_data2 |
+------+------+--------+---------------+---------------+
| 1    | 1    | 0      | 15.556        | 5.556         |
| 1    | 1    | 1      | 14.996        | 4.996         |
| 1    | 1    | 2      | 12.556        | NaN           |
| 1    | 1    | 3      | 15.669        | NaN           |
+------+------+--------+---------------+---------------+

So the he final query is:

select mi.key1, mi.key2, p12.serial, mi.info1, mi.info2, mi.date, p12.product_data1, p12.product_data2 
from main_info mi 
inner join p12 on mi.key1 = p12.key1 and mi.key2 = p12.key2
order by mi.key1, mi.key2, p12.serial;


+------+------+--------+-------+-------+----------+---------------+---------------+
| key1 | key2 | serial | info1 | info2 | date     | product_data1 | product_data2 |
+------+------+--------+-------+-------+----------+---------------+---------------+
| 1    | 1    | 0      | 15    | 90    | 20120501 | 15.556        | 5.556         |
| 1    | 1    | 1      | 15    | 90    | 20120501 | 14.996        | 4.996         |
| 1    | 1    | 2      | 15    | 90    | 20120501 | 12.556        | NaN           |
| 1    | 1    | 3      | 15    | 90    | 20120501 | 15.669        | NaN           |
| 1    | 2    | 0      | 14    | 92    | 20120601 | 12.556        | 2.556         |
| 1    | 2    | 1      | 14    | 92    | 20120601 | 13.335        | 3.335         |
| 1    | 2    | 2      | 14    | 92    | 20120601 | NaN           | 2.56          |
| 1    | 2    | 3      | 14    | 92    | 20120601 | NaN           | 3.556         |
| 1    | 3    | 1      | 15    | 82    | 20120801 | 12.225        | 2.225         |
| 1    | 3    | 2      | 15    | 82    | 20120801 | 13.556        | 3.556         |
| 1    | 3    | 3      | 15    | 82    | 20120801 | 14.556        | NaN           |
| 2    | 1    | 0      | 17    | 90    | 20130302 | 12.556        | NaN           |
| 2    | 1    | 1      | 17    | 90    | 20130302 | 13.553        | NaN           |
| 2    | 1    | 2      | 17    | 90    | 20130302 | 12.335        | NaN           |
| 2    | 2    | 0      | 16    | 88    | 20130601 | NaN           | 2.556         |
| 2    | 2    | 1      | 16    | 88    | 20130601 | NaN           | 3.553         |
+------+------+--------+-------+-------+----------+---------------+---------------+

Best Answer

Related Solutions

Product Attribute List Design Pattern in MySQL

MySQL – How to Merge 3 Tables with Conditions

Related Question