MySql sort conditional based on column values

conditionMySQLsorting

I have a table with products where there's a column for price and stock.

I want the products to be display sorted by the following rules:

All products with price = 0 go to the bottom;
Then the products with price are sorted by:
- if stock is greater or equal to 100 then they are sorted by price ASC;
- else they are sorted by stock DESC and if there's a draw then sorted by price ASC.

So far I came up with price = 0, stock >= 100 DESC, price ASC, stock DESC
which seems to work correctly when there's products with stock over 100 but falls apart when there are none.

SELECT * 
FROM products 
ORDER BY price = 0, stock >= 100 DESC, price ASC, stock DESC

How can I make this work?

Best Answer

I think this would work - although it's rather obfuscated:

ORDER BY 
    price = 0, 
    LEAST(stock, 100) DESC, 
    price ;

More clearly:

ORDER BY 
    CASE WHEN price > 0 THEN 1 ELSE 2 END, 
    CASE WHEN stock >= 100 THEN 100 ELSE stock END DESC, 
    price ;

Related Solutions

MySQL : Conditional ORDER BY to only one column

SELECT* FROM mytable ORDER BY
LOCATE(CONCAT('.',`group`,'.'),'.9.7.6.10.8.5.');

I took your sample data, loaded it into a table called mytable and ran it.

Here are the results:

mysql> use test
Database changed
mysql> drop table if exists mytable;
Query OK, 0 rows affected (0.04 sec)

mysql> create table mytable
    -> (
    ->    names varchar(10),
    ->    `group` int
    -> );
Query OK, 0 rows affected (0.08 sec)

mysql> insert into mytable values
    -> ('susanita',  10),
    -> ('miguelito', 5),
    -> ('mafalda',   7),
    -> ('manolito',  8),
    -> ('libertad',  6),
    -> ('felipe',    9),
    -> ('guille',    8);
Query OK, 7 rows affected (0.09 sec)
Records: 7  Duplicates: 0  Warnings: 0

mysql> SELECT * FROM mytable;
+-----------+-------+
| names     | group |
+-----------+-------+
| susanita  |    10 |
| miguelito |     5 |
| mafalda   |     7 |
| manolito  |     8 |
| libertad  |     6 |
| felipe    |     9 |
| guille    |     8 |
+-----------+-------+
7 rows in set (0.00 sec)

mysql> SELECT * FROM mytable ORDER BY
    -> LOCATE(CONCAT('.',`group`,'.'),'.9.7.6.10.8.5.');
+-----------+-------+
| names     | group |
+-----------+-------+
| felipe    |     9 |
| mafalda   |     7 |
| libertad  |     6 |
| susanita  |    10 |
| manolito  |     8 |
| guille    |     8 |
| miguelito |     5 |
+-----------+-------+
7 rows in set (0.01 sec)

mysql>

Give it a Try !!!

UPDATE 2011-09-06 12:33 EDT

Here is another approach:

SELECT* FROM mytable ORDER BY
IF(FIELD(`group`,9,7,6,10,8,5)=0,99999,FIELD(`group`,9,7,6,10,8,5));

This will force any groups other than 9,7,6,10,8,5 to appear at the very bottom of the query.

UPDATE 2011-09-06 14:39 EDT

mysql> SELECT names, `group`
    -> FROM mytable
    -> WHERE `group` IN (9,7,6,10,8,5)
    -> ORDER BY find_in_set(`group`,'9,7,6,10,8,5');
+-----------+-------+
| names     | group |
+-----------+-------+
| felipe    |     9 |
| mafalda   |     7 |
| libertad  |     6 |
| susanita  |    10 |
| manolito  |     8 |
| guille    |     8 |
| miguelito |     5 |
+-----------+-------+
7 rows in set (0.00 sec)

Hey @Nick, yours works as well against my sample data !!!

Mysql – execute a prepared statement inside a MySQL SELECT

From the question, it looks like what you have written quasi-resembles what Oracle calls an anonymous code block. MySQL does not facilitate such a mechanism.

With regard to what you want to accomplish, you do not need a stored procedure.

Try assembling the SQL statement like this:

@stmt = 'SELECT sid, ifnull(pricelist,"BASE"), count(*) AS recs FROM buyerList AS b ';
@stmt = CONCAT(@stmt,'LEFT JOIN sellerList AS s ON s.sid = b.sid AND s.pass = b.pass ');
@stmt = CONCAT(@stmt,'LEFT JOIN pricelists p ON ');
SELECT GROUP_CONCAT(CONCAT('(p.sid = a.sid AND p.preisliste = ',sid,' AND p.ean = a.ean AND p.iln = ',pricelist',)') SEPARATOR ' OR ')
INTO @LeftJoinClause FROM preislisten;
@stmt = CONCAT(@stmt,@LeftJoinClause,' WHERE b.bid = ?');
SELECT @stmt\G

This will print out the desired query

If it is the desired query, execute it

PREPARE sql FROM @stmt;
EXECUTE sql using @param_iln;
DEALLOCATE PREPARE sql;

Give it a Try !!!

If you actually want the query to be small without hardcoding every value just write the code with a more straightforward LEFT JOIN setup

SELECT p.sid, ifnull(p.pricelist,"BASE"), count(*) AS recs FROM buyerList AS b
LEFT JOIN sellerList AS s ON s.sid = b.sid AND s.pass = b.pass
LEFT JOIN pricelists p ON
    (p.sid = a.sid AND p.preisliste = a.sid AND p.ean = a.ean)
WHERE b.bid = ?
GROUP BY p.sid,p.pricelist;

I also just noticed you have a.sid and a.ean, what table has an alias of a ?

Best Answer

Related Solutions

MySQL : Conditional ORDER BY to only one column

Mysql – execute a prepared statement inside a MySQL SELECT

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