Mysql – Select count(*), where 2 rows with different values exists

SELECT A.*
FROM default_relations_users A
LEFT JOIN default_relations_users B
ON  A.id_user_rq = B.id_user_ap
AND A.id_user_ap = B.id_user_rq
WHERE B.id_user_rq IS NULL;

I loaded you sample data (I added an additional index)

mysql> use Reynierpm
Database changed
mysql> DROP TABLE IF EXISTS `default_relations_users`;
Query OK, 0 rows affected (0.00 sec)

mysql> CREATE TABLE IF NOT EXISTS `default_relations_users` (
    ->   `id_user_rq` int(11) NOT NULL,
    ->   `id_user_ap` int(11) NOT NULL,
    ->   UNIQUE KEY `rusers_rq_ap_idx` (`id_user_rq`,`id_user_ap`),
    ->   UNIQUE KEY `rusers_ap_eq_idx` (`id_user_ap`,`id_user_rq`)
    -> ) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;
Query OK, 0 rows affected (0.05 sec)

mysql> INSERT INTO `default_relations_users` (`id_user_rq`, `id_user_ap`) VALUES
    -> (1, 2), (1, 3), (1, 4), (2, 1), (2, 2), (2, 3);
Query OK, 6 rows affected (0.00 sec)
Records: 6  Duplicates: 0  Warnings: 0

mysql> select * from default_relations_users;
+------------+------------+
| id_user_rq | id_user_ap |
+------------+------------+
|          1 |          2 |
|          1 |          3 |
|          1 |          4 |
|          2 |          1 |
|          2 |          2 |
|          2 |          3 |
+------------+------------+
6 rows in set (0.00 sec)

mysql>

Here is the result of my answer

mysql> SELECT A.*
    -> FROM default_relations_users A
    -> LEFT JOIN default_relations_users B
    -> ON  A.id_user_rq = B.id_user_ap
    -> AND A.id_user_ap = B.id_user_rq
    -> WHERE B.id_user_rq IS NULL;
+------------+------------+
| id_user_rq | id_user_ap |
+------------+------------+
|          1 |          3 |
|          1 |          4 |
|          2 |          3 |
+------------+------------+
3 rows in set (0.00 sec)

mysql>

Give it a Try !!!

mysql> SELECT A.*
    -> FROM default_relations_users A
    -> LEFT JOIN default_relations_users B
    -> ON  A.id_user_rq = B.id_user_ap
    -> AND A.id_user_ap = B.id_user_rq
    -> WHERE B.id_user_rq IS NULL
    -> AND A.id_user_rq = 1;
+------------+------------+
| id_user_rq | id_user_ap |
+------------+------------+
|          1 |          3 |
|          1 |          4 |
+------------+------------+
2 rows in set (0.01 sec)

mysql>

Ok, first off I think you are almost there. From looking at the schema and data one thing I have noticed is that you seem to have overlooked the fact that a friendship is bi-directional. So when you create a friend entry from a request you also need to create one in the other direction as well:

INSERT INTO `default_friend` (`friend_id`, `user_id`, `is_suscriber`, `privacy`, `created_at`, `friend_list_id`, `approved`) 
VALUES (1, 2, 1, 0, '2012-08-13 18:16:11', 0, 1);

After you have done that your query should be more like the result you are after. Running this query:

select distinct u.id as `user_id`, u.username, f.id as `friend_id`, f.username as friend, s.*
from default_users as u
left join default_friend as df on df.user_id = u.id
left join default_users as f on f.id = df.friend_id
left join default_status as s on s.user_id = u.id
left join default_comment as c on c.status_id = s.status_id
order by s.status_id;

returns the following result set:

user_id username    friend_id   friend  status_id   message created_at  privacy user_id is_reply    device  
1   admin   2   demo    1   dasdasdasdasdasd    2012-08-13 19:45:37 NULL    1   0   
2   demo    1   admin   2   dasdasdasdasdasd    2012-08-13 19:46:03 NULL    2   0   
1   admin   2   demo    3   dasdsad344hbvnbnhjhgjhjghjhj    2012-08-13 21:54:53 NULL    1   0

Is this anywhere near what you are looking for?