From here, I modified the query slightly to get
select adddate('2015-02-01', numlist.id) as `my_date`,
weekday(adddate('2015-02-01', numlist.id)) as day_no,
dayname(adddate('2015-02-01', numlist.id)) as `day_name`
from
(SELECT n1.i + n10.i*10 + n100.i*100 AS id
FROM num n1 cross join num as n10 cross join num as n100) as numlist
where adddate('2015-02-01', numlist.id) <= '2015-02-28'
and dayname(adddate('2015-02-01', numlist.id)) in( 'Monday', 'Tuesday');
which gives
+------------+--------+----------+
| my_date | day_no | day_name |
+------------+--------+----------+
| 2015-02-02 | 0 | Monday |
| 2015-02-03 | 1 | Tuesday |
| 2015-02-09 | 0 | Monday |
| 2015-02-10 | 1 | Tuesday |
| 2015-02-16 | 0 | Monday |
| 2015-02-17 | 1 | Tuesday |
| 2015-02-23 | 0 | Monday |
| 2015-02-24 | 1 | Tuesday |
+------------+--------+----------+
8 rows in set (0.01 sec)
or from here
select * from
(select adddate('1970-01-01',t4*10000 + t3*1000 + t2*100 + t1*10 + t0) selected_date from
(select 0 t0 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
(select 0 t1 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
(select 0 t2 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
(select 0 t3 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3,
(select 0 t4 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t4) v
where selected_date between '2015-02-01' and '2015-02-28'
and dayname(selected_date) in ('Monday', 'Tuesday');
result
+---------------+
| selected_date |
+---------------+
| 2015-02-02 |
| 2015-02-03 |
| 2015-02-09 |
| 2015-02-10 |
| 2015-02-16 |
| 2015-02-17 |
| 2015-02-23 |
| 2015-02-24 |
+---------------+
8 rows in set (0.23 sec)
CREATE TABLE mydate( blah date);
INSERT INTO mydate (blah)
select adddate('2015-02-01', numlist.id) as `my_date`
-- weekday(adddate('2015-02-01', numlist.id)) as day_no,
-- dayname(adddate('2015-02-01', numlist.id)) as `day_name`
from
(SELECT n1.i + n10.i*10 + n100.i*100 AS id
FROM num n1 cross join num as n10 cross join num as n100) as numlist
where adddate('2015-02-01', numlist.id) <= '2015-05-28'
and dayname(adddate('2015-02-01', numlist.id)) in( 'Monday', 'Tuesday');
(need a table num)
mysql> select * from mydate;
+------------+
| blah |
+------------+
| 2015-02-02 |
| 2015-02-03 |
| 2015-02-09 |
| 2015-02-10 |
| 2015-02-16 |
| 2015-02-17 |
| 2015-02-23 |
| 2015-02-24 |
| 2015-03-02 |
OR
insert into mydate (blah)
select * from
(select adddate('1970-01-01',t4*10000 + t3*1000 + t2*100 + t1*10 + t0) selected_date from
(select 0 t0 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
(select 0 t1 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
(select 0 t2 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
(select 0 t3 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3,
(select 0 t4 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t4) v
where selected_date between '2015-02-01' and '2015-05-28'
and dayname(selected_date) in ('Monday', 'Tuesday');
No table necessary. Same result as above.
Best Answer
I have written a stored routines called month_weeks. It accepts two parameters, the month and the year and output a list of weeks. It uses a temporary table to calculate the start and the end of weeks. For example:
returns:
The text of routine is: