MySQL – Retrieve Total Available Days in Date Range

dateMySQL

Given the following MySQL database structure for a booking system, how can I retrieve all available days between two user supplied dates?

| ID | code  | date_arrival | date_departure
| 4  | APT01 | 2015-04-10   | 2015-04-15
| 5  | APT01 | 2015-04-22   | 2015-04-29
| 6  | APT02 | 2015-04-11   | 2015-04-19
| 8  | APT02 | 2015-04-20   | 2015-04-25

For example: The user enters 2015-04-16 as their start date and 2015-04-28 as their end date. The available days over this period are 16th – 21st using APT01, and 26th – 27th using APT02

This means there are 8 available days out of those requested by the user. How can I query the data and get 8 as my result?

Best Answer

First solution

Well, I tried a solution. It works but it is pretty ugly. But it works...

SELECT count(*)
FROM (
    SELECT code, dates.selected_date
    FROM appartments
    INNER JOIN (select * from 
      (select adddate('2015-01-01',t3.i*1000 + t2.i*100 + t1.i*10 + t0.i) selected_date from
       (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
       (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
       (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
       (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3) v
    WHERE selected_date BETWEEN '2015-04-16' AND '2015-04-28') dates
    WHERE (code, selected_date) NOT IN (
        SELECT code, dates.selected_date
        FROM appartments
        INNER JOIN (select * from 
          (select adddate('2015-01-01',t3.i*1000 + t2.i*100 + t1.i*10 + t0.i) selected_date from
           (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
           (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
           (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
           (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3) v
          ) dates ON dates.selected_date between date_arrival and date_departure)
    GROUP BY code, dates.selected_date) available_dates_by_code

Change the date period in the line WHERE selected_date BETWEEN '2015-04-16' AND '2015-04-28') dates.

Remove the first level SELECT FROM to get all dates of unoccupied apartments for dates between '2015-04-16' AND '2015-04-28'.

You may want to change the '2015-01-01' dates to something earlier (ie. CURDATE() if you're only working with future dates). This query will only return next 30 years dates past '2015-01-01', so change it to something like CURDATE() - '1 YEAR'

I'm very curious to see if someone have a better solution...

How it works

From the bottom to the top :

The first SELECT gets all occupied dates for all appartments.
The second SELECT gets all dates wanted and removes all appartment/date couples that are occupied.
The third select count the number of appartement/date couple available between the provided dates.

Second solution

SELECT
  (
    SELECT adddate('2015-01-01',t3.i*1000 + t2.i*100 + t1.i*10 + t0.i) selected_date
    FROM apartments
    INNER JOIN (SELECT * FROM 
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3) v
    WHERE selected_date BETWEEN '2015-04-16' AND '2015-04-28'
  ) -
  (
    SELECT count (code, dates.selected_date)
    FROM apartments
    INNER JOIN (SELECT * FROM
      (select adddate('2015-01-01',t3.i*1000 + t2.i*100 + t1.i*10 + t0.i) selected_date from
       (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
       (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
       (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
       (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3) v
      ) dates ON dates.selected_date between date_arrival and date_departure
    WHERE selected_date BETWEEN '2015-04-16' AND '2015-04-28'
  ) AS 'days_of_availability'

This one is much more simpler. The second SELECT counts the number of days existing for the two dates multiplied by the number of apartments. The third SELECT counts the number of occupied days for all the apartments. The top SELECT does (number of days) minus (number of occupied days).

Fun fact: it took me almost 30 minutes to get this query working. That's a shame.

Related Solutions

MySQL – Query to Find Records Between Two Date Ranges

Your query has a logical flaw: it tries to find people who are NOT in the list of people who DO have coaching but only if the coaching is NOT in the target window.

Instead, join the employee and coaching table on employee_id, using all rows in employee but only using rows in coaching where the stop_date is later than or equal to the desired start date (coaching ends after the window starts) and the the start_date is less than or equal to the desired stop date (coaching starts before the window ends). Then exclude the employees with one or more matching rows in coaching.

SELECT e.id AS employee_id
  FROM employee e
  LEFT JOIN coaching c ON c.employee_id = e.id
                      AND c.end_date >= '2014-12-26'
                      AND c.start_date <= '2015-01-30'
 WHERE c.employee_id IS NULL;

Live demo: http://sqlfiddle.com/#!9/79b39/4

MySQL – How to Select All Mondays Between Two Dates

From here, I modified the query slightly to get

select adddate('2015-02-01', numlist.id) as `my_date`, 
       weekday(adddate('2015-02-01', numlist.id)) as day_no,
       dayname(adddate('2015-02-01', numlist.id)) as `day_name` 
from
(SELECT n1.i + n10.i*10 + n100.i*100 AS id
   FROM num n1 cross join num as n10 cross join num as n100) as numlist
where adddate('2015-02-01', numlist.id) <= '2015-02-28'
and dayname(adddate('2015-02-01', numlist.id)) in( 'Monday', 'Tuesday');

which gives

+------------+--------+----------+
| my_date    | day_no | day_name |
+------------+--------+----------+
| 2015-02-02 |      0 | Monday   |
| 2015-02-03 |      1 | Tuesday  |
| 2015-02-09 |      0 | Monday   |
| 2015-02-10 |      1 | Tuesday  |
| 2015-02-16 |      0 | Monday   |
| 2015-02-17 |      1 | Tuesday  |
| 2015-02-23 |      0 | Monday   |
| 2015-02-24 |      1 | Tuesday  |
+------------+--------+----------+
8 rows in set (0.01 sec)

or from here

select * from 
(select adddate('1970-01-01',t4*10000 + t3*1000 + t2*100 + t1*10 + t0) selected_date from
 (select 0 t0 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
 (select 0 t1 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
 (select 0 t2 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
 (select 0 t3 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3,
 (select 0 t4 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t4) v
where selected_date between '2015-02-01' and '2015-02-28'
and dayname(selected_date) in ('Monday', 'Tuesday');

result

+---------------+
| selected_date |
+---------------+
| 2015-02-02    |
| 2015-02-03    |
| 2015-02-09    |
| 2015-02-10    |
| 2015-02-16    |
| 2015-02-17    |
| 2015-02-23    |
| 2015-02-24    |
+---------------+
8 rows in set (0.23 sec)


CREATE TABLE mydate( blah date);

INSERT INTO mydate (blah)
select adddate('2015-02-01', numlist.id) as `my_date`
--       weekday(adddate('2015-02-01', numlist.id)) as day_no,
--       dayname(adddate('2015-02-01', numlist.id)) as `day_name` 
from
(SELECT n1.i + n10.i*10 + n100.i*100 AS id
   FROM num n1 cross join num as n10 cross join num as n100) as numlist
where adddate('2015-02-01', numlist.id) <= '2015-05-28'
and dayname(adddate('2015-02-01', numlist.id)) in( 'Monday', 'Tuesday');

(need a table num)

mysql> select * from mydate;
+------------+
| blah       |
+------------+
| 2015-02-02 |
| 2015-02-03 |
| 2015-02-09 |
| 2015-02-10 |
| 2015-02-16 |
| 2015-02-17 |
| 2015-02-23 |
| 2015-02-24 |
| 2015-03-02 |

insert into mydate (blah) 
select * from 
(select adddate('1970-01-01',t4*10000 + t3*1000 + t2*100 + t1*10 + t0) selected_date from
 (select 0 t0 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
 (select 0 t1 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
 (select 0 t2 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
 (select 0 t3 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3,
 (select 0 t4 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t4) v
where selected_date between '2015-02-01' and '2015-05-28'
and dayname(selected_date) in ('Monday', 'Tuesday');

No table necessary. Same result as above.