Here is a query I wrote up to give you the most recent thursday and the ending wednesday
SELECT thuwk_beg + INTERVAL 0 second thu_beg,
thuwk_beg + INTERVAL 604799 second wed_end
FROM (SELECT (DATE(NOW()) - INTERVAL daysbacktothursday DAY) thuwk_beg
FROM (SELECT SUBSTR('3456012',wkndx,1) daysbacktothursday
FROM (SELECT DAYOFWEEK(dt) wkndx FROM (SELECT DATE(NOW()) dt) AAAA) AAA) AA) A;
Here is an example for today, 2011-09-21
mysql> SELECT
-> thuwk_beg + INTERVAL 0 second thu_beg,
-> thuwk_beg + INTERVAL 604799 second wed_end
-> FROM (SELECT (DATE(NOW()) - INTERVAL daysbacktothursday DAY) thuwk_beg
-> FROM (SELECT SUBSTR('3456012',wkndx,1) daysbacktothursday
-> FROM (SELECT DAYOFWEEK(dt) wkndx FROM (SELECT DATE(NOW()) dt) AAAA) AAA) AA) A;
+---------------------+---------------------+
| thu_beg | wed_end |
+---------------------+---------------------+
| 2011-09-15 00:00:00 | 2011-09-21 23:59:59 |
+---------------------+---------------------+
1 row in set (0.00 sec)
Just replace the NOW() function calls with whatever datetime you like and you will have the week starting Thursday all the time for the give datetime you choose.
Here is another example using the specific date '2011-01-01'
mysql> SELECT
-> thuwk_beg + INTERVAL 0 second thu_beg,
-> thuwk_beg + INTERVAL 604799 second wed_end
-> FROM (SELECT (DATE('2011-01-01') - INTERVAL daysbacktothursday DAY) thuwk_beg
-> FROM (SELECT SUBSTR('3456012',wkndx,1) daysbacktothursday
-> FROM (SELECT DAYOFWEEK(dt) wkndx FROM (SELECT DATE('2011-01-01') dt) AAAA) AAA) AA) A;
+---------------------+---------------------+
| thu_beg | wed_end |
+---------------------+---------------------+
| 2010-12-30 00:00:00 | 2011-01-05 23:59:59 |
+---------------------+---------------------+
1 row in set (0.00 sec)
Your query of table
referencing today would resemble something like this:
SELECT * from `table`,
(SELECT thuwk_beg + INTERVAL 0 second thu_beg,
thuwk_beg + INTERVAL 604799 second wed_end
FROM (SELECT (DATE(NOW()) - INTERVAL daysbacktothursday DAY) thuwk_beg
FROM (SELECT SUBSTR('3456012',wkndx,1) daysbacktothursday
FROM (SELECT DAYOFWEEK(dt) wkndx FROM (SELECT DATE(NOW()) dt) AAAA) AAA) AA) A) M
WHERE `date` >= thu_beg
AND `date` <= wed_end;
Give it a Try !!!
UPDATE 2011-09-22 16:27 EDT
This was my proposed query for marking Thu-Wed.
SELECT thuwk_beg + INTERVAL 0 second thu_beg,
thuwk_beg + INTERVAL 604799 second wed_end
FROM (SELECT (DATE(NOW()) - INTERVAL daysbacktothursday DAY) thuwk_beg
FROM (SELECT SUBSTR('3456012',wkndx,1) daysbacktothursday
FROM (SELECT DAYOFWEEK(dt) wkndx FROM (SELECT DATE(NOW()) dt) AAAA) AAA) AA) A;
How about other weeks ???
(SELECT SUBSTR('6012345',wkndx,1)
does the week starting Mon ending Sun
(SELECT SUBSTR('5601234',wkndx,1)
does the week starting Tue ending Mon
(SELECT SUBSTR('4560123',wkndx,1)
does the week starting Wed ending Tue
(SELECT SUBSTR('3456012',wkndx,1)
does the week starting Thu ending Wed
(SELECT SUBSTR('2345601',wkndx,1)
does the week starting Fri ending Thu
(SELECT SUBSTR('1234560',wkndx,1)
does the week starting Sat ending Fri
(SELECT SUBSTR('0123456',wkndx,1)
does the week starting Sun ending Sat
There is a manual page on Time and Date functions.
The best way to compare date and time and get minutes back is probably to use one of the following:
SELECT TIME_TO_SEC(TIMEDIFF(timea,timeb)+0)/60
SELECT TIMESTAMPDIFF(MINUTE,timeb,timea)
Note that while TIMEDIFF
works with times, TIMESTAMPDIFF
requires a date component - and the values are switched around for TIMESTAMPDIFF
.
You can return hours with either of these:
SELECT TIME_TO_SEC(TIMEDIFF(timea,timeb)+0)/60/60
SELECT TIMESTAMPDIFF(HOUR,timeb,timea)
Note that when using DATEDIFF
, the value returned is a difference between the date components of the given time - thus, a value of 23:59 on one day compared to a value of 0:01 on the next (a 2 minute difference) results in a date difference of 1 (a full day).
To get a difference between two times in 24-hour periods (length of a day) first calculate the difference in minutes then divide by the proper values to find the number of 24-hour periods. Try this:
SELECT TRUNCATE(TIMESTAMPDIFF(MINUTE,timeb,timea)/60.0/24.0,0)
This truncates the decimal portion, returning only the number of complete 24-hour periods in the specified timespan.
Best Answer
Since
OpenDate
is adatetime
column, you don't need to useDATE_FORMAT()
, you can simplyGROUP BY DATE(OpenDate)
. And the extraCRC32()
call seem completely redundant.The query can be rewritten:
Add an index on
(ListID, UserID, OpenDate)
, to make it more efficient.