Ms-access – Minimum value on most recent date per account MS ACCESS SQL

greatest-n-per-groupms access

I have a MS ACCESS DB table Riskscore with the three fields: CHACCTBS, CHRQDATE, CHSCORE and want to find the lowest CHSCORE on the most recent CHRQDATE per CHACCTBS where it is possible to have multiple CHSCORE values on the same CHRQDATE. There should be one record returned for each CHACCTBS. There are about 17,000 records. Once the query has run, there should be 7008 records returned.

CHACCTBS, CHRQDATE, CHSCORE
101    1/1/2014    781
101    1/1/2014    791
101    12/31/2013   717
221    10/01/2013   512
235    1/2/2014     685
235    10/31/2013   600

The query should return:

101    1/1/2014    781
221    10/01/2013   512
235    1/2/2014     685

Thanks!

Best Answer

This would be a good place to use window functions if your RDBMS supports them. The example below is T-SQL so if you are not on SQL Server you may have to adapt the syntax and/or keywords.

Window Functions are ANSI Standard starting with SQL:2003, and as such you likely have access to them with any modern RDBMS. If you are on SQL Server read about their implementation of Window Functions here.

SELECT CHACCTBS, CHRQDATE, CHSCORE
FROM
(
    SELECT
         MIN(CHSCORE) OVER(PARTITION BY CHACCTBS) As CHACCTBS
        ,CHRQDATE
        ,CHSCORE
        ,ROW_NUMBER() OVER(PARTITION BY CHACCTBS ORDER BY CHRQDATE DESC, CHSCORE) As Limiter
    FROM RiskScore
) X
WHERE Limiter = 1

The subquery returns your MIN and other columns, and creates a filter by assigning row numbers by your partition and ordered by descending dates. You then take the first row of each partition in the WHERE clause.

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Ms-access – Query – Match Name to Multiple Unique Types

-- this should work for a starter
select distinct MyTable.Name, MyTable.Type
from MyTable
where Name in (
        select t1.Name
        from (
            select t0.Name, t0.Type
            from (
                select distinct MyTable.Name, MyTable.Type
                from MyTable
                ) as t0
            group by t0.Name, t0.Type
            ) as t1
        group by t1.Name
        having count(*) > 1
        );

Ms-access – SQL queries to only show most recent purchase records for individual food items

MS Access is rather limited.

I assume that it is possible to have more than one invoice for the same date. In this case I'll pick an invoice with the highest ID.

At first we'll find maximum Invoice Date for each Food Item.

SELECT
    FPD1.[Food item ID] AS ItemID
    ,MAX(I1.[Invoice Date]) AS MaxDate
FROM
    [Food purchase data] AS FPD1
    INNER JOIN Invoices AS I1 ON I1.ID = FPD1.[Invoice ID]
GROUP BY
    FPD1.[Food item ID]

Since it is possible that there are several invoices for the found max date we'll pick one invoice with the max ID per Item

Based on the MS Access syntax of nested joins and using this example from the docs:

SELECT fields 
FROM 
  table1 INNER JOIN 
  (
      table2 INNER JOIN 
      (
          table3 INNER JOIN tablex ON table3.field3 = tablex.fieldx
      ) ON table2.field2 = table3.field3
  ) ON table1.field1 = table2.field2
;

Let's try to put it together:

SELECT
    InvoicesMaxDate.ItemID
    ,InvoicesMaxDate.MaxDate
    ,MAX(I2.ID) AS MaxInvoiceID
FROM
    (
        SELECT
            FPD1.[Food item ID] AS ItemID
            ,MAX(I1.[Invoice Date]) AS MaxDate
        FROM
            [Food purchase data] AS FPD1
            INNER JOIN Invoices AS I1 ON I1.ID = FPD1.[Invoice ID]
        GROUP BY
            FPD1.[Food item ID]
    ) AS InvoicesMaxDate INNER JOIN
    (
        [Food purchase data] AS FPD2 
        INNER JOIN Invoices AS I2 ON I2.ID = FPD2.[Invoice ID]
    ) ON
        InvoicesMaxDate.ItemID = FPD2.[Food item ID] AND
        --- you may need to put extra "ON" here as well, not sure
        InvoicesMaxDate.MaxDate = I2.[Invoice Date]
GROUP BY
    InvoicesMaxDate.ItemID
    ,InvoicesMaxDate.MaxDate

Now we have both ItemID and ID of the last Invoice for that Item. Join this to original tables to fetch other details (columns).

SELECT
    FI3.Item
    ,FI3.Item
    ,FPD3.[Price per unit]
    ,FPD3.[Purchase unit]
    ,I3.[Invoice Date]
FROM
    (
        SELECT
            InvoicesMaxDate.ItemID
            ,InvoicesMaxDate.MaxDate
            ,MAX(I2.ID) AS MaxInvoiceID
        FROM
            (
                SELECT
                    FPD1.[Food item ID] AS ItemID
                    ,MAX(I1.[Invoice Date]) AS MaxDate
                FROM
                    [Food purchase data] AS FPD1
                    INNER JOIN Invoices AS I1 ON I1.ID = FPD1.[Invoice ID]
                GROUP BY
                    FPD1.[Food item ID]
            ) AS InvoicesMaxDate INNER JOIN
            (
                [Food purchase data] AS FPD2 
                INNER JOIN Invoices AS I2 ON I2.ID = FPD2.[Invoice ID]
            ) ON
                InvoicesMaxDate.ItemID = FPD2.[Food item ID] AND
                InvoicesMaxDate.MaxDate = I2.[Invoice Date]
        GROUP BY
            InvoicesMaxDate.ItemID
            ,InvoicesMaxDate.MaxDate
    ) AS LastInvoices INNER JOIN
    (
        [Food items] AS FI3 INNER JOIN
        (
            [Food purchase data] AS FPD3
            INNER JOIN Invoices AS I3 ON I3.ID = FPD3.[Invoice ID]
        ) ON FI3.ID = FDP3.[Food item ID]
    ) ON
        LastInvoices.MaxInvoiceID = I3.ID AND
        LastInvoices.ItemID = FI3.ID

In practice I'd create a view for the first query with a single join. Then I'd create a second view that joins the first view with the tables, then the third view and so on, to avoid the nested joins or minimize them. Overall query would be easier to read.

Edit to clarify what I mean based on your final solution that you put into the question.

One last attempt to convey my message.

This is what you wrote based on my suggestions above:

SELECT
    InvoicesMaxDate.ItemID
    ,InvoicesMaxDate.MaxDate
    ,Invoices.[Invoice ID]
FROM [Food purchase data], Invoices, 
    (
        SELECT 
            [Food purchase data].[Food item ID] AS ItemID
            ,MAX(Invoices.[Invoice Date]) AS MaxDate
        FROM [Food purchase data], Invoices
        WHERE Invoices.[Invoice ID] = [Food purchase data].[Invoice ID]
        GROUP BY [Food purchase data].[Food item ID]
    )  AS InvoicesMaxDate
WHERE
    Invoices.[Invoice ID] = [Food purchase data].[Invoice ID] AND
    InvoicesMaxDate.ItemID = [Food purchase data].[Food item ID] AND 
    InvoicesMaxDate.MaxDate = Invoices.[Invoice Date]
GROUP BY InvoicesMaxDate.ItemID, InvoicesMaxDate.MaxDate, Invoices.[Invoice ID];

This is what I meant:

SELECT
    InvoicesMaxDate.ItemID
    ,InvoicesMaxDate.MaxDate
    ,MAX(Invoices.[Invoice ID]) AS [Invoice ID]
FROM [Food purchase data], Invoices, 
    (
        SELECT
            [Food purchase data].[Food item ID] AS ItemID
            ,MAX(Invoices.[Invoice Date]) AS MaxDate
        FROM [Food purchase data], Invoices
        WHERE Invoices.[Invoice ID] = [Food purchase data].[Invoice ID]
        GROUP BY [Food purchase data].[Food item ID]
    )  AS InvoicesMaxDate
WHERE
    Invoices.[Invoice ID] = [Food purchase data].[Invoice ID] AND
    InvoicesMaxDate.ItemID = [Food purchase data].[Food item ID] AND 
    InvoicesMaxDate.MaxDate = Invoices.[Invoice Date]
GROUP BY InvoicesMaxDate.ItemID, InvoicesMaxDate.MaxDate;

Do you see the difference?

The InvoicesMaxDate returns MAX Invoice Date for each Food item ID. If there are two invoices for the same Food item ID with the same MAX Invoice Date we should pick one invoice among them. This is done by grouping by InvoicesMaxDate.ItemID, InvoicesMaxDate.MaxDate. There should be no grouping by Invoices.[Invoice ID] here, because we want to pick the invoice with the maximum ID.

Once you have this query saved as a LatestInvoices view, it is used further as you correctly wrote (note, that the final query uses LatestInvoices.[Invoice ID] and LatestInvoices.ItemID, but doesn't use LatestInvoices.MaxDate):

SELECT 
    [Food items].ID as FoodItemID
    ,[Food items].Item as FoodItem
    ,[Food purchase data].[Price]
    ,[Food purchase data].[Price per unit]
    ,[Food purchase data].[Purchase unit]
    ,Invoices.[Invoice Date]
FROM [Food items], [Food purchase data], Invoices, LatestInvoices
WHERE 
    Invoices.[Invoice ID] = [Food purchase data].[Invoice ID] AND
    [Food items].ID = [Food purchase data].[Food item ID] AND
    LatestInvoices.[Invoice ID] = Invoices.[Invoice ID] AND 
    LatestInvoices.ItemID = [Food items].ID
ORDER BY [Food items].Item

As for, why your last query in the question returns several rows per Item:

SELECT 
    [Food purchase data].[Food item ID]
    , [Food purchase data].[Price per unit]
    , max(Invoices.[Invoice Date]) AS MostRecentInvoiceDate
FROM [Food purchase data], Invoices
GROUP BY [Food purchase data].[Food item ID], [Food purchase data].[Price per unit];

You are grouping here by [Food item ID] and [Price per unit], so you'll get as many rows as there are unique combinations of these two columns.

The following query would return one row per [Food item ID].

SELECT 
    [Food purchase data].[Food item ID]
    , max(Invoices.[Invoice Date]) AS MostRecentInvoiceDate
FROM [Food purchase data], Invoices
GROUP BY [Food purchase data].[Food item ID];

A side note, you really should use explicit INNER JOIN instead of ,. That syntax is 20 years old.

SELECT 
    [Food purchase data].[Food item ID]
    , max(Invoices.[Invoice Date]) AS MostRecentInvoiceDate
FROM
    [Food purchase data]
    INNER JOIN Invoices ON Invoices.ID = [Food purchase data].[Invoice ID]
GROUP BY [Food purchase data].[Food item ID];

Best Answer

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