Localtimestamp or curent_timestamp for default value

There is a manual page on Time and Date functions.

The best way to compare date and time and get minutes back is probably to use one of the following:

SELECT TIME_TO_SEC(TIMEDIFF(timea,timeb)+0)/60
SELECT TIMESTAMPDIFF(MINUTE,timeb,timea)

Note that while TIMEDIFF works with times, TIMESTAMPDIFF requires a date component - and the values are switched around for TIMESTAMPDIFF.

You can return hours with either of these:

SELECT TIME_TO_SEC(TIMEDIFF(timea,timeb)+0)/60/60
SELECT TIMESTAMPDIFF(HOUR,timeb,timea)

Note that when using DATEDIFF, the value returned is a difference between the date components of the given time - thus, a value of 23:59 on one day compared to a value of 0:01 on the next (a 2 minute difference) results in a date difference of 1 (a full day).

To get a difference between two times in 24-hour periods (length of a day) first calculate the difference in minutes then divide by the proper values to find the number of 24-hour periods. Try this:

SELECT TRUNCATE(TIMESTAMPDIFF(MINUTE,timeb,timea)/60.0/24.0,0)

This truncates the decimal portion, returning only the number of complete 24-hour periods in the specified timespan.

Here are a couple of approaches:

I've simplified your query, as you shouldn't need the TRUNC(), nor the CAST().

SELECT to_timestamp(1395036000) AT TIME ZONE 'UTC';

SELECT timestamp '1970-01-01 00:00:00' + interval '1395036000 second';

For reference, more information can be found at the following links:

• First query

• Second query