How to convert execution time to a specific format

the result of the expression

to_date('1970-01-01','YYYY-MM-DD') + numtodsinterval(1244108886,'SECOND')

is a value of the oracle datatype DATE. This type contains date and time. If you want to display this value to a user you must convert it to a string. This conversion can be done by an application or you can let oracle convert it to a string type as it is done in this example. This automatic conversion to the oracle stringtype VARCHAR2 is controlled by nls_date_format and some server settings. If you want your view to return a VARCHAR2 value with the calculated date in the format 'YYYY-MM-DD HH24:MI:SS' and not a DATE value you can do this by using a conversion function: expression

to_char(to_date('1970-01-01','YYYY-MM-DD') + numtodsinterval(1244108886,'SECOND'),'YYYY-MM-DD HH24:MI:SS')

But in this case the return value of the view is a VARCHAR2 and not a DATE value.

Instead of your hack with replace, why not just cast to the right data type? This doesn't need to be nvarchar and the only reason it contains time is because you included too many characters. You can of course apply your replace here as well (or you could do that at the client).

SELECT CONVERT(CHAR(11),GETDATE(),13)
UNION ALL
SELECT CONVERT(CHAR(11), DATEADD(DAY, 10, GETDATE()), 13);

Results:

27 Aug 2012
06 Sep 2012