Get max date for each year from list of dates

dategroup bysql-standard

Need to get max date for each year from list of arbitrary dates:

date         year
=================
1/10/2013    2013
3/26/2013    2013
4/20/2012    2012
9/10/2012    2012
5/6/2011     2011

So with a working query, using the above data, the correct result would be:

maxdate     year
=================
3/26/2013    2013
9/10/2012    2012
5/6/2011     2011

Our database is proprietary, supporting only ANSI-SQL, no fancy extensions.
Tried using group_by, but it's retrieving all dates for each year, not what I want.

Best Answer

It is possible that I am missing something, but you should be able to get the result easily using the max() aggregate and a GROUP BY:

select
  max(date) maxdate,
  year
from yourtable
group by year;

See SQL Fiddle with Demo

Related Solutions

Sql-server – SQL join query to show rows with non-existent rows in one table

Thank you for SQLfiddle and sample data! I wish more questions started this way.

If you want all members regardless of whether they have an entry for that date, you want a LEFT OUTER JOIN. You were very close with this version however a little trick with outer joins is that if you add a filter to the outer table in the WHERE clause, you turn an outer join to an inner join, because it will exclude any rows that are NULL on that side (because it doesn't know if NULL would match the filter or not).

I modified the first query to get a row for every member:

SELECT Members.Member_ID
      ,Time_Entry.Date_Start
      ,Time_Entry.Hours_Actual
      ,Time_Entry.Hours_Bill
FROM dbo.Members
  LEFT OUTER JOIN dbo.Time_Entry
--^^^^ changed from FULL to LEFT
  ON Members.Member_ID = Time_Entry.Member_ID
  AND Time_Entry.Date_Start = '20131110';
--^^^ changed from WHERE to AND

I'll leave it as an exercise for the reader to take it from there and add the other columns, formatting, COALESCE etc.

Some other notes:

please always use the schema prefix when creating and referencing objects
please always use a length when converting to varchar etc.
stay away from ambiguous, regional date formats like mm-dd-yyyy

consider using aliases to make your queries easier to read. E.g. the above could be re-written as:

SELECT m.Member_ID
  ,t.Date_Start
  ,t.Hours_Actual
  ,t.Hours_Bill
FROM dbo.Members AS m
LEFT OUTER JOIN dbo.Time_Entry AS t
ON m.Member_ID = t.Member_ID
AND t.Date_Start = '20131110';

... a lot tidier, IMHO, as long as you use sensible aliases.

Mysql – How to get dates that wrap around new year from non-datetime columns

You can use MAKEDATE(), it makes the day_of_year to a date.

Test:

mysql> SELECT * FROM cli_table;
+-------+--------------+-------------+-------+
| month | day_of_month | day_of_year | value |
+-------+--------------+-------------+-------+
|     1 |            1 |           1 | 23.00 |
|     1 |            2 |           2 | 22.95 |
|    12 |           31 |         365 | 23.12 |
+-------+--------------+-------------+-------+
3 rows in set (0.00 sec)

mysql> SELECT 
    -> MAKEDATE(YEAR(CURDATE()),day_of_year) AS Date,
    ->     value AS DayValue
    -> FROM test.cli_table;
+------------+----------+
| Date       | DayValue |
+------------+----------+
| 2015-01-01 |    23.00 |
| 2015-01-02 |    22.95 |
| 2015-12-31 |    23.12 |
+------------+----------+
3 rows in set (0.00 sec)

mysql>

You can try it in this Fiddle.

EDIT:

According of what you want, you can make it with pure SQL:

mysql> SELECT * FROM test.cli_table;
+-------+--------------+-------------+-------+
| month | day_of_month | day_of_year | value |
+-------+--------------+-------------+-------+
|     1 |            1 |           1 |  5.00 |
|     1 |            2 |           2 |  6.00 |
|     1 |            3 |           3 |  7.00 |
|    12 |           25 |         359 | 23.00 |
|    12 |           26 |         360 | 22.95 |
|    12 |           27 |         361 |  1.00 |
|    12 |           28 |         362 |  2.00 |
|    12 |           29 |         363 |  3.00 |
|    12 |           30 |         364 |  4.00 |
|    12 |           31 |         365 | 23.12 |
+-------+--------------+-------------+-------+
10 rows in set (0.00 sec)

mysql> SELECT 
    -> v.selected_date,
    -> v.dayyear,
    -> c.value AS DayValue,
    -> c.day_of_year 
    -> FROM test.cli_table AS c
    -> JOIN (SELECT 
    -> adddate('1970-01-01',t4.i*10000 + t3.i*1000 + t2.i*100 + t1.i*10 + t0.i) AS selected_date,
    -> DAYOFYEAR(adddate('1970-01-01',t4.i*10000 + t3.i*1000 + t2.i*100 + t1.i*10 + t0.i)) AS dayyear
    -> FROM 
    -> (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
    -> (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
    -> (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
    -> (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3,
    -> (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t4) AS v
    -> ON (v.selected_date between '2015-12-25' AND '2016-01-03'
    -> AND v.dayyear=c.day_of_year);
+---------------+---------+----------+-------------+
| selected_date | dayyear | DayValue | day_of_year |
+---------------+---------+----------+-------------+
| 2015-12-25    |     359 |    23.00 |         359 |
| 2015-12-26    |     360 |    22.95 |         360 |
| 2015-12-27    |     361 |     1.00 |         361 |
| 2015-12-28    |     362 |     2.00 |         362 |
| 2015-12-29    |     363 |     3.00 |         363 |
| 2015-12-30    |     364 |     4.00 |         364 |
| 2015-12-31    |     365 |    23.12 |         365 |
| 2016-01-01    |       1 |     5.00 |           1 |
| 2016-01-02    |       2 |     6.00 |           2 |
| 2016-01-03    |       3 |     7.00 |           3 |
+---------------+---------+----------+-------------+
10 rows in set (0.00 sec)

mysql>

Query Meaning:

SELECT 
    v.selected_date,
    v.dayyear,
    c.value AS DayValue,
    c.day_of_year 
FROM test.cli_table AS c
--- > This JOIN is generating all the dates between the selected_dates ('2015-12-25' AND '2016-01-03')
JOIN (SELECT 
        adddate('1970-01-01',t4.i*10000 + t3.i*1000 + t2.i*100 + t1.i*10 + t0.i) AS selected_date,
        DAYOFYEAR(adddate('1970-01-01',t4.i*10000 + t3.i*1000 + t2.i*100 + t1.i*10 + t0.i)) AS dayyear
      FROM 
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3,
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t4) AS v
--- > Here I'm matching every dayyear of the generated dates with the cli_table.day_of_year.
ON (v.selected_date between '2015-12-25' AND '2016-01-03'
    AND v.dayyear=c.day_of_year);