In my project I have a number of jar-files, resources, h2 database, etc. I launch my application by executing a shell-script with configuration params.
I would like to create Mac app by using Platypus. However after creation I can't launch it. Could anyone help me?
I set script path and add all my resources like this:
After I create an app (Optimize Application) and try to launch it I receive the following error:
/Users/Mac/SPI/Reader Plat/Start Irule
Client.app/Contents/Resources/script: /Users/Mac/SPI/Reader Plat/Start
Irule Client.app/Contents/Resources/script: is a directory
My shell-script is the following:
#!/bin/bash
export IRULE_HOME="$(cd "$(dirname "$0")" && pwd -P)"
export IRULE_LANG=en
export IRULE_REGION=EN
export IRULE_XMS=-Xms256m
export IRULE_XMX=-Xmx1024m
export LOG4J_CONFIGURATION=${IRULE_HOME}/conf/log4j2.xml
export JAVA_HOME="${IRULE_HOME}/jre/Contents/Home"
export DEFAULT_JVM_OPTS="$IRULE_XMS \
$IRULE_XMX \
-Dlog4j.configuration=file:"${LOG4J_CONFIGURATION}" \
-Dirule.home=${IRULE_HOME} \
-Dirule.client.logs.path=${IRULE_HOME}/logs \
-Duser.language="${IRULE_LANG}" \
-Duser.region="${IRULE_REGION}" \
$JAVA_OPTS"
export PATH=${JAVA_HOME}/bin:${JAVA_HOME}:${PATH}
export CLASSPATH=${IRULE_HOME}/lib/*:${IRULE_HOME}/conf:${JAVA_HOME}/lib/jfxrt.jar;
echo "IRULE_HOME="${IRULE_HOME}
echo "IRULE_XMS="${IRULE_XMS}
echo "IRULE_XMX="${IRULE_XMX}
${JAVA_HOME}/bin/java -version
exec ${JAVA_HOME}/bin/java -Xdock:name="iRule Reader" -Xdock:icon=${IRULE_HOME}/image/irule.png ${DEFAULT_JVM_OPTS} -classpath "${CLASSPATH}" com.spi2.Main $*
How to solve the issue and successfully launch the app?
Best Answer
The issue was with the name of the directories and app that are separated by spaces.
For some reasons removing spaces solve the issue.